即使没有实施,uilongpressgesturerecognizer也会崩溃

Question

我尝试了所有可能的搜索,但我在一周内没有找到类似的东西.我正在创建一个显示表视图的应用程序.单元格(由自定义类和Interface Builder制作)可以使用属于Cell类的UIPanGestureRecognizer进行拖动.一切正常,但是当我将手指按在单元格上时,应用程序会因错误而崩溃:

-[UILongPressGestureRecognizer translationInView:]: unrecognized selector sent to instance 0x94670a0
*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UILongPressGestureRecognizer translationInView:]: unrecognized selector sent to instance 0x94670a0'

我知道它的意思(通常是一个错误的参数发送到实例),但我真的不知道这怎么可能,因为我的代码中没有UILongPressGestureRecognizer的痕迹.我试图拦截LongPressGestureREcognizer无处不在(在细胞类,在tableview中的类,每一个细胞的分配之前),但错误还是一样的(我看了许多线程在这里的主题,相信我,语法是正确的.

如果你想要任何其他文件随意问(这是我在这里的第一篇文章,我不知道我要展示的内容).

谢谢你的宝贵帮助.

好吧问题仍然是抱歉打扰:(我不知何故设法设置断点并打印堆栈跟踪.这里是:

0   uBellow                             0x0000ac57 -[OpinionCell gestureRecognizerShouldBegin:] + 71
1   UIKit                               0x00914939 -[UIGestureRecognizer _shouldBegin] + 1334
2   UIKit                               0x0091181a -[UIGestureRecognizer setState:] + 152
3   UIKit                               0x00921cea -[UILongPressGestureRecognizer enoughTimeElapsed:] + 127
4   libobjc.A.dylib                     0x017186b0 -[NSObject performSelector:withObject:] + 70
5   UIKit                               0x00787954 -[UIDelayedAction timerFired:] + 83
6   Foundation                          0x0114d2c0 __NSFireTimer + 97
7   CoreFoundation                      0x01bce376 __CFRUNLOOP_IS_CALLING_OUT_TO_A_TIMER_CALLBACK_FUNCTION__ + 22
8   CoreFoundation                      0x01bcde06 __CFRunLoopDoTimer + 534
9   CoreFoundation                      0x01bb5a82 __CFRunLoopRun + 1810
10  CoreFoundation                      0x01bb4f44 CFRunLoopRunSpecific + 276
11  CoreFoundation                      0x01bb4e1b CFRunLoopRunInMode + 123
12  GraphicsServices                    0x022337e3 GSEventRunModal + 88
13  GraphicsServices                    0x02233668 GSEventRun + 104
14  UIKit                               0x00648ffc UIApplicationMain + 1211
15  uBellow                             0x0000287d main + 141
16  uBellow                             0x000027a5 start + 53

应用程序阻止代码:

-(BOOL)gestureRecognizerShouldBegin:(UIPanGestureRecognizer *)gestureRecognizer {
CGPoint translation = [gestureRecognizer translationInView:[self superview]];

编辑我通过截取UILongPressGestureRecognizer解决了,这是一种安全的方法吗？

-(BOOL)gestureRecognizerShouldBegin:(UIPanGestureRecognizer *)gestureRecognizer {
if([gestureRecognizer isKindOfClass:[UILongPressGestureRecognizer class]]){
    return NO;
}else{
CGPoint translation = [gestureRecognizer translationInView:[self superview]];
// Check for horizontal gesture
if (fabsf(translation.x) > fabsf(translation.y)){
    return YES;
}
}
return NO;}

Answer 1

我通过检查您收到的gestureRecognizer 的类型解决了这个问题.

有时候我收到的是" UILongPressGestureRecognizer"而不是" UIPanGestureRecognizer".

试试这个:

-(BOOL)gestureRecognizerShouldBegin:(UIPanGestureRecognizer *)gestureRecognizer {
    if ([gestureRecognizer class] == [UIPanGestureRecognizer class]) {
        CGPoint translation = [gestureRecognizer translationInView:[self superview]];

        return YES;
    }
    return NO;
}

更新

Swift 2.0版

override func gestureRecognizerShouldBegin(gestureRecognizer: UIGestureRecognizer) -> Bool {
    guard let panGestureRecognizer = gestureRecognizer as? UIPanGestureRecognizer else { return false }

    let translation = panGestureRecognizer.translationInView(self.superview)
}