Rob*_*tto 3 c# xml-serialization
我正在尝试将XML序列化为对象.但是,我遇到了一些麻烦.我可能已经在网上发布了关于答案的帖子,但我还没弄清楚.请让我解释一下:
我有以下要序列化的XML:
<Import_RootObject>
<Organizations>
<Import_Organization OrgNr="xxxx">
<Events>
<Import_Event StartTime="2012-01-01 09:00:00" EndTime="2012-01-02 12:00:00">
<Players>
<Import_Player PersonNummer="1111" />
<Import_Player PersonNummer="2222" />
<Import_Player PersonNummer="3333" />
<Import_Player PersonNummer="4444" />
</Players>
</Import_Event>
</Events>
</Import_Organization>
</Organizations>
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我使用四个类来捕获这个XML:
using System;
using System.Collections.Generic;
using System.Xml.Serialization;
[XmlRoot("Import_RootObject")]
public class Import_RootObject
{
[XmlArray("organizations")]
[XmlArrayItem("organizations")]
public List<Import_Organization> Organizations { get; set; }
}
using System;
using System.Collections.Generic;
using System.Xml.Serialization;
public class Import_Organization
{
[XmlAttribute("orgnr")]
public string OrgNr { get; set; }
[XmlArray("events")]
[XmlArrayItem("events")]
public List<Import_Event> Events { get; set; }
}
using System;
using System.Collections.Generic;
using System.Xml.Serialization;
public class Import_Event
{
[XmlAttribute("starttime")]
public DateTime StartTime { get; set; }
[XmlAttribute("endtime")]
public DateTime EndTime { get; set; }
[XmlArray("players")]
[XmlArrayItem("players")]
public List<Import_Player> Players { get; set; }
}
using System;
using System.Collections.Generic;
using System.Xml.Serialization;
public class Import_Player
{
[XmlAttribute]
public string PersonNummer { get; set; }
}
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我用来反序列化的代码是:
XmlSerializer serializer = new XmlSerializer(typeof(Import_Organization));
Import_RootObject ei = (Import_RootObject)serializer.Deserialize(new StringReader(sb.ToString()));
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而我得到的错误是:
There is an error in XML document (1, 2).
<Import_RootObject xmlns=''> was not expected.
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有谁知道我在这里缺少什么?希望有人可以帮忙!
问候,
短发
第一个明显的错误是:
XmlSerializer serializer = new XmlSerializer(typeof(Import_Organization));
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当然应该是:
XmlSerializer serializer = new XmlSerializer(typeof(Import_RootObject));
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但是,您还应注意xml区分大小写:
[XmlArray("organizations")]
[XmlArrayItem("organizations")]
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应该:
[XmlArray("Organizations")]
[XmlArrayItem("Import_Organization")]
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匹配xml; 同样
[XmlArray("events")]
[XmlArrayItem("events")]
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应该:
[XmlArray("Events")]
[XmlArrayItem("Import_Event")]
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和:
[XmlArray("players")]
[XmlArrayItem("players")]
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应该:
[XmlArray("Players")]
[XmlArrayItem("Import_Player")]
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另外,请注意,<Players>它不是后代Import_Event- 它是其中的一部分Events.这使生活变得有点复杂.
然后我们注意到您的日期不是"starttime"/"endtime",因此我们可以简化为:
[XmlAttribute]
public DateTime StartTime { get; set; }
[XmlAttribute]
public DateTime EndTime { get; set; }
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除了......那些日期/时间无效xml日期/时间 - 它们格式错误.所以你现在可能不得不将它们视为string数据.
最后,您的xml格式错误 - 您尚未关闭根元素.
坦率地说,我并不觉得序列化器不喜欢那样:)
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