这是我在C中进行线程化的第一次尝试.我正在创建一个循环有界的缓冲区.我知道如何创建线程,但我看到的所有示例都只有接受一个void参数的线程函数,但不幸的是我的工作者规范要求我使用三个,如下所示:
void bufferRead(BoundedBuffer* buffer, char* data, int count) {
pthread_mutex_lock(&buffer->mutexBuffer);
<snip>
pthread_mutex_unlock(&buffer->mutexBuffer);
}
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这是我的pthread_create语句
pthread_create(&buffer.readThread, NULL, (void *)bufferRead, &readParams)
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和我的readParams结构/赋值
struct readThreadParams {
BoundedBuffer b;
char* data;
int count;
};
struct readThreadParams readParams;
readParams.b = buffer2;
readParams.data = out_array;
readParams.count = in_size;
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关于如何在传递给bufferRead函数之后分配每个struct的参数的任何建议将不胜感激.
那是因为你只需要一个参数.当我们有多个值时(通常就是这种情况),我们将其封装到结构中.pthread_create将调用的函数类型是不可协商的.这是一个区域,你的函数指针的类型转换会让你陷入严重的麻烦.
#include <pthread.h>
#include <stdlib.h>
struct BoundedBuffer {
pthread_t readThread;
pthread_mutex_t mutexBuffer;
} buffer2;
struct readThreadParams {
struct BoundedBuffer b;
char* data;
int count;
};
void *bufferRead (void *context) {
struct readThreadParams *readParams = context;
pthread_mutex_lock(&readParams->b.mutexBuffer);
//<snip>
pthread_mutex_unlock(&readParams->b.mutexBuffer);
return NULL;
}
int main(void) {
int ret;
char *out_array = malloc(42);
size_t in_size = 42;
struct readThreadParams readParams;
readParams.b = buffer2;
readParams.data = out_array;
readParams.count = in_size;
/* I presume that by "buffer", you really meant the .b member of
* struct readThreadParams. Further, this must have a member
* named readThread of type pthread_t, etc.
*/
ret = pthread_create(&readParams.b.readThread, NULL, bufferRead, &readParams);
if (!ret) {
pthread_join(&readParams.b.readThread, NULL);
}
free(out_array);
return ret;
}
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