Top*_*opo 4 arrays postgresql bitstring postgresql-9.2
我有一个160个字符串的字符串,我需要一个整数数组来存储值为1的位的位置.
例:
bitstring = '00110101'
array = [3,4,6,8]
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是否可以仅使用SQL执行此操作,还是需要定义PL/SQL函数或类似的东西?
确实可以用SQL编写它.这是一个起点:
select array(
select substring(str from i for 1) as bit
from generate_series(1, length(str)) as i
where bit = '1'
);
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不过,您可能希望将其包装在pl/sql函数中,以避免在整个地方重复代码.
工作功能:
create or replace function get_bit_positions(varbit) returns bit[] as $$
select array(
select substring($1 from i for 1) as bit
from generate_series(1, length($1)) as i
where substring($1 from i for 1) = '1'
);
$$ language sql immutable;
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工作版本:
WITH x AS (SELECT '00110101'::varbit AS b)
SELECT array_agg(i)
FROM (SELECT b, generate_series(1, length(b)) AS i FROM x) y
WHERE substring(b, i, 1) = '1';
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更简单,一旦你转换varbit到text[].投奔text并运行string_to_array().
然后你可以generate_subscripts()按索引使用和选择数组元素:
WITH x AS (SELECT string_to_array('00110101'::varbit::text, NULL) AS b)
SELECT array_agg(i)
FROM (SELECT b, generate_subscripts(b,1) AS i FROM x) y
WHERE b[i] = '1'
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