如何使用jQuery访问Object Literal中项目的名称?
例如,我将如何读取"标题","链接","媒体"等内容
{
"title": "What we do in our free time...",
"link": "http://www.flickr.com/photos/tnhimmies/4042938515/",
"media": {"m":"http://farm3.static.flickr.com/2572/4042938515_3a00561320_m.jpg"},
"date_taken": "2009-10-24T03:48:10-08:00",
"description": "<p><a href=\"http://www.flickr.com/people/tnhimmies/\">Darlene, TN Persians (www.tnpurrs.com)<\/a> posted a photo:<\/p> <p><a href=\"http://www.flickr.com/photos/tnhimmies/4042938515/\" title=\"What we do in our free time...\"><img src=\"http://farm3.static.flickr.com/2572/4042938515_3a00561320_m.jpg\" width=\"240\" height=\"230\" alt=\"What we do in our free time...\" /><\/a><\/p> <p>Tennessee Persians<br /> <a href=\"http://www.tnpurrs.com\" rel=\"nofollow\">www.tnpurrs.com<\/a><\/p>",
"published": "2009-10-25T18:28:36Z",
"author": "nobody@flickr.com (Darlene, TN Persians (www.tnpurrs.com))",
"author_id": "66405213@N00",
"tags": "cat persian tnpurrs"
},
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CMS*_*CMS 21
您还可以使用$ .each函数:
var obj = { one:1, two:2, three:3, four:4, five:5 };
$.each(obj, function(key, value) {
//..
});
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如果你采用for...in语句方式,我建议你检查属性是否直接驻留在被迭代的对象上,因为如果扩展了Object.prototype ,你可能会遇到一些 问题:
for(var key in obj) {
if (obj.hasOwnProperty(key)){
// value = obj[key];
}
}
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for (var key in json) {
// ...
}
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(这是标准的javascript,而不是jQuery-speficic)
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