HHC*_*HHC 8 haskell persistent yesod
所以我的/ config/models看起来像这样.
Person
name Text
Car
name Text
PersonCar
personId PersionId eq
carId CarId eq
UniquePersonCar personId carId
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假设数据库中的输入Person "Batman"
Person "Superman"
Car "SUV"
Car "Ford"
分别是.
我正在这样做,以便在我的处理程序中将它们链接起来.
runDB $ do
person <- selectFirst [PersonName ==. "Batman"] []
car <- selectFirst [Carname ==. "SUV"] []
let Entity personId _ = case person of
Just info -> infor
Nothing -> error "no such Person"
let Entity carId _ = case car of
Just info -> infor
Nothing -> error "no such Car"
_ <- insert $ PersonCar personId carId
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有更简单的方法吗?做这样的表达是否有约定?
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