Doctrine查询构建选择MAX

Question

我想选择所有+ MAX值并仅接收具有最大值的行.

    $query = $this->createQueryBuilder('s');
    $query->where('s.challenge = :challenge')->setParameter('challenge', $challenge);
    $query->groupBy('s.score');
    $query->getQuery();

    return $query->select('s.*, MAX(s.score) AS max_score')->getQuery()->getResult();

我怎么能在学说中实现这一点？我收到一个错误*找不到属性.我试图一个接一个地选择它们,但也没有运气.

目标是实现这样的目标

SELECT user, challenge, whateverelse, MAX(score) FROM users_scores_table GROUP BY user_id

请帮忙 ;)

Answer 1

这是一个最终的工作查询

    $query = $this->createQueryBuilder('s');
    $query->select('s, MAX(s.score) AS max_score');
    $query->where('s.challenge = :challenge')->setParameter('challenge', $challenge);
    $query->groupBy('s.user');
    $query->setMaxResults($limit);
    $query->orderBy('max_score', 'DESC');

    return $query->getQuery()->getResult();

Answer 2

现在为时已晚,但我为记录写了这篇文章.

您可以在SELECT语句中使用"as HIDDEN"来删除最终结果的字段,这样您就可以将其用于排序或分组而无需修改结果字段.

在你的例子中:

$query = $this->createQueryBuilder('s');
$query->select('s, MAX(s.score) AS HIDDEN max_score');
$query->where('s.challenge = :challenge')->setParameter('challenge', $challenge);
$query->groupBy('s.user');
$query->setMaxResults($limit);
$query->orderBy('max_score', 'DESC');