在sql server中使用类似查询二进制列

use*_*523 8 sql-server sql-server-2008

我正在使用SQL Server 2008.在我的表中,我有一个名为TestDatatype 的列binary.

TestData列中的示例数据是

1. 0x0001DC780C0030373156635D0C00B8840301009A0600AC
2. 0x0301DC780C0030373156385D0C006499C401009A0600AC
Run Code Online (Sandbox Code Playgroud)

写下面两个查询以获取TestData以"0x0001"开头的行.但他们都没有工作.

SELECT * 
FROM T_TRANSACTION 
WHERE  CAST(Indicium AS nvarchar(MAX)) LIKE '0x0001%'

----No results found

SELECT * 
FROM T_TRANSACTION 
WHERE  CAST(Indicium AS nvarchar(MAX)) LIKE '0x0001%'

----Returns all the rows
Run Code Online (Sandbox Code Playgroud)

请更正查询以获得预期结果

gbn*_*gbn 12

不要转换它,但是视为一个范围(就像你的日期时间值一样)

DECLARE @foo TABLE (TestData varbinary(100) NOT NULL);
INSERT @foo (TestData) VALUES
         (0x0001DC780C0030373156635D0C00B8840301009A0600AC),
         (0x0001AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA),
         (0x0001AFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF),
         (0x0301DC780C0030373156385D0C006499C401009A0600AC),
         (0x0301FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF),
         (0x0302000000000000000000000000000000000000000000);

SELECT *
FROM @foo
WHERE TestData >= 0x0001 AND TestData < 0x0002;

-- added more digit for clarity of what actually happens
SELECT *
FROM @foo
WHERE TestData >= 0x00010000 AND TestData < 0x00020000;

SELECT *
FROM @foo
WHERE TestData >= 0x0001AA AND TestData < 0x0001AB;

SELECT *
FROM @foo
WHERE TestData >= 0x0301 AND TestData < 0x0302;
Run Code Online (Sandbox Code Playgroud)

这具有能够在TestData上使用索引的好处

编辑,您只需指定所需的数字