G. *_*rdi 5 boost boost-spirit boost-fusion variadic-templates c++11
我正在寻找实现variadic函数的最简单方法,它采用boost :: spirit :: qi规则列表并将列表扩展为格式表达式:rule1 | rule2 | rule3 | ....让我们假设规则不合成任何属性.非常感谢您的帮助.
#include <boost/config/warning_disable.hpp>
#include <boost/spirit/include/qi.hpp>
#include <string>
#include <iostream>
#include <boost/spirit/include/phoenix_operator.hpp>
namespace qi = boost::spirit::qi;
namespace ph = boost::phoenix;
namespace ascii = boost::spirit::ascii;
using boost::spirit::qi::phrase_parse;
using boost::spirit::qi::ascii::space;
using boost::spirit::iso8859_1::char_;
typedef qi::rule<std::string::const_iterator,ascii::space_type> mrule_t;
typedef qi::rule< std::string::const_iterator,std::string() > wrule_t;
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//How to deduce expandBitwise() return type ?
template<typename T>
T expandBitwise(T& t)
{
return t.rule_;
}
template<typename T,typename ...Tail>
T expandBitwise(T& t,Tail& ...tail)
{
return t.rule_ | expandBitwise(tail...);
}
struct TStruct
{
mrule_t rule_;
template<typename T,typename R>
TStruct( T& rVar,const std::string&name, R& rule ) :
rule_( qi::lit( name ) >> rule[ ph::ref( rVar )=qi::_1 ] )
{}
};
template<typename T,typename ...Tail>
void mparse(const std::string& line,T& t,Tail& ...tail)
{
std::string::const_iterator f,l;
f=line.begin();
l=line.end();
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// I would like to expand the rules here ...
//if(phrase_parse(f,l,expandBitwise(t,tail...),space ) && f==l)
if( phrase_parse(f, l, t.rule_, space ) && f==l )
std::cout<<"Parsed:"<<line<<std::endl;
else
std::cout<<"Syntax error:"<<line<<std::endl;
}
int main()
{
wrule_t rword=+~space;
std::string par1,par2,par3,par4;
TStruct r1( par1,"-a", rword );
TStruct r2( par2,"-b", rword );
TStruct r3( par3,"-c", rword );
TStruct r4( par4,"-d", rword );
mparse("abc 8.81" ,r1,r2,r3,r4);
mparse("-a atoken" ,r1,r2,r3,r4);
mparse("-b btoken" ,r1,r2,r3,r4);
mparse("-c ctoken" ,r1,r2,r3,r4);
mparse("-d dtoken" ,r1,r2,r3,r4);
return 0;
}
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谢谢你的快速提示!我刚试过你的代码,除非我做错了什么......我得到了这个输出:
Syntax error:abc 8.81 Parsed:-a atoken Syntax error:-b btoken Syntax error:-c ctoken Syntax error:-d dtoken
- G. Civardi 2小时前
好吧,所以,我不能不管它:/
事实证明存在未定义的行为,因为解析器表达式被传递expandBitwise
和复制的方式:Boost Proto表达式模板不是为了复制而设计的,因为它们可能包含对temporaries的引用,temporaries的生命周期结束于他们包含完整的表达.
有关更多背景信息,请参阅2秒内零至60英里/小时的讨论!
经过很长一段时间的调整后rule_.alias()
,boost::proto::deepcopy
我已经达到了以下解决方案(顺便说一下,根本不再需要帮助函数):
template<typename ...Tail>
void mparse(const std::string& line,Tail& ...tail)
{
auto parser = boost::fusion::fold(
boost::tie(ph::bind(&TStruct::rule_, arg1)(tail)...),
qi::eps(false),
deepcopy_(arg2 | arg1)
);
auto f=begin(line), l=end(line);
if( qi::phrase_parse(f, l, parser, ascii::space ) )
std::cout << "Parsed:" << line << std::endl;
else
std::cout << "Syntax error:" << line << std::endl;
if (f!=l)
std::cout << "Remaining unparsed: '" << std::string(f,l) << "'\n";
}
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对UB的保护是deepcopy_()
调用,它是一个简单的多态可调用适配器,用于boost::proto::deepcopy
:
struct DeepCopy
{
template<typename E> struct result { typedef typename boost::proto::result_of::deep_copy<E>::type type; };
template<typename E>
typename result<E>::type
operator()(E const& expr) const {
return boost::proto::deep_copy(expr);
}
};
static const ph::function<DeepCopy> deepcopy_;
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使用此代码,请注意,输出变为:
Syntax error:abc 8.81
Remaining unparsed: 'abc 8.81'
Parsed:-a atoken
Parsed:-b btoken
Parsed:-c ctoken
Parsed:-d dtoken
Bye
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作为奖励,代码现在允许您使用Spirit的内置debug()功能(取消注释该行):
<-d>
<try>abc 8.81</try>
<fail/>
</-d>
<-c>
<try>abc 8.81</try>
<fail/>
</-c>
<-b>
<try>abc 8.81</try>
<fail/>
</-b>
<-a>
<try>abc 8.81</try>
<fail/>
</-a>
Syntax error:abc 8.81
Remaining unparsed: 'abc 8.81'
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经过测试
- 提升1_54_0
- GCC 4.7.2,4.8.x,Clang 3.2
- 注意
#define
s是重要的.
#define BOOST_RESULT_OF_USE_DECLTYPE
#define BOOST_SPIRIT_USE_PHOENIX_V3
#include <boost/fusion/adapted/boost_tuple.hpp>
#include <boost/fusion/include/fold.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
namespace qi = boost::spirit::qi;
namespace ph = boost::phoenix;
namespace ascii = boost::spirit::ascii;
using namespace ph::arg_names;
typedef qi::rule<std::string::const_iterator,ascii::space_type> mrule_t;
typedef qi::rule<std::string::const_iterator,std::string() > wrule_t;
struct TStruct
{
mrule_t rule_;
template<typename T,typename R>
TStruct( T& rVar,const std::string&name, R& rule ) :
rule_( qi::lit(name) >> rule[ ph::ref(rVar) = qi::_1 ] )
{
rule_.name(name);
// debug(rule_);
}
};
struct DeepCopy
{
template<typename E> struct result { typedef typename boost::proto::result_of::deep_copy<E>::type type; };
template<typename E>
typename result<E>::type
operator()(E const& expr) const {
return boost::proto::deep_copy(expr);
}
};
static const ph::function<DeepCopy> deepcopy_;
template<typename ...Tail>
void mparse(const std::string& line,Tail& ...tail)
{
auto parser = boost::fusion::fold(
boost::tie(ph::bind(&TStruct::rule_, arg1)(tail)...),
qi::eps(false),
deepcopy_(arg2 | arg1)
);
auto f=begin(line), l=end(line);
if( qi::phrase_parse(f, l, parser, ascii::space ) )
std::cout << "Parsed:" << line << std::endl;
else
std::cout << "Syntax error:" << line << std::endl;
if (f!=l)
std::cout << "Remaining unparsed: '" << std::string(f,l) << "'\n";
}
int main()
{
wrule_t rword=+~ascii::space;
std::string par1,par2,par3,par4;
TStruct r1( par1, "-a", rword );
TStruct r2( par2, "-b", rword );
TStruct r3( par3, "-c", rword );
TStruct r4( par4, "-d", rword );
mparse("abc 8.81" ,r1,r2,r3,r4);
mparse("-a atoken" ,r1,r2,r3,r4);
mparse("-b btoken" ,r1,r2,r3,r4);
mparse("-c ctoken" ,r1,r2,r3,r4);
mparse("-d dtoken" ,r1,r2,r3,r4);
std::cout << "Bye\n";
}
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