获取字符串中的特定字符串数

Question

如果我有这样的字符串:

$string = '01122028K,02122028M,03122028K,04122028M,05122028K,06122028P-2,07122028K,08122028P-';

如何在字符串$ string中获取'K'的数量.在这种情况下,K将是4.我知道它可以通过帮助strpos()在将$ string分解为数组之后通过循环来解决.有任何PHP功能以直截了当的方式完成吗？

谢谢.

Answer 1

echo "There are " . substr_count($string, 'K') . " K's in the string";

如果你不想数K-1这个可以是:

echo "There are " . substr_count($string, 'K')-substr_count($string, 'K-') . " K's in the string";

要在评论中解决新问题:

$string = '01122028K,02122028M,02122028K-1,02122028K-2,03122028K,04122028M,05122028K-1,04122028M,05122028K,06122028P-2,07122028K,08122028P-';
preg_match_all('/K(?:-\d+)?/', $string, $match);
$counts = array_count_values($match[0]);
print_r($counts);

Array
(
    [K] => 4
    [K-1] => 2
    [K-2] => 1
)