Mac*_*_97 7 php forms variables post
我已经创建了一个注册表单,成功地将其变量从注册页面(go-gold.php)传递到摘要/验证页面(go-gold-summary.php).数据在第二页上正确显示.
但是,我希望能够使用图像按钮返回到注册页面,以防用户输入错误.回过头来,现在应该使用首次输入的数据填充原始表单.
问题是我无法从第二页重新发送/返回数据,回到第一页.我的文本字段显示为空白.我不想使用Session变量.
代码将从整个页面中截断.
注册页面(go-gold.php):
<?php
$customer_name = $_POST['customer_name'];
?>
<form action="go-gold-summary.php" method="post">
Name: <input type="text" name="customer_name" id="customer_name" value= "<?php echo $customer_name ?>" />
<input name="<?php echo $customer_name ?>" type="hidden" id="<?php echo $customer_name ?>">
</form>
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摘要页面(go-gold-summary.php)
<?php
$customer_name = $_POST['customer_name'];
?>
<form action="go-gold.php" method="post">
Name: <?php echo $customer_name ?> <input type="hidden" id="<?php echo $customer_name ?>" name="<?php echo $customer_name ?>">
<INPUT TYPE="image" src="images/arrow_back.png" id="arrow" alt="Back to Registration"> (Button to go back to Registration Page)
</form>
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谢谢!
go-gold-summary.php应该这样更改。
<?php
$customer_name = $_POST['customer_name'];
?>
<form action="go-gold.php" method="post">
Name: <?php echo $customer_name ?> <input type="hidden" value="<?php echo $customer_name ?>" name="customer_name">
<INPUT TYPE="submit" src="images/arrow_back.png" id="arrow" alt="Back to Registration"> (Button to go back to Registration Page)
</form>
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注意我如何改变这一行
<input type="hidden" id="<?php echo $customer_name ?>" name="<?php echo $customer_name ?>">
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进入这个
<input type="hidden" value="<?php echo $customer_name ?>" name="customer_name">
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$_POST 是一个关联数组,当您提交表单时,它将按如下方式填充:
$_POST["index"] = value;
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其中"index"是文本字段“名称”,value是文本字段值。
您在代码中错过了这一点。只需用我的代码更新它就可以了