从日期时间中提取时间并确定时间(不是日期)是否在范围内？

Question

问题是我希望它忽略日期,只考虑时间因素.这是我有的:

import time
from time import mktime
from datetime import datetime

def getTimeCat(Datetime):
    # extract time categories
    str_time = datetime.strptime(Datetime, "%m/%j/%y %H:%M")
    ts = datetime.fromtimestamp(mktime(str_time))

    # --> Morning = 0400-1000
    mornStart = datetime.time(4, 0, 1)
    mornEnd = datetime.time(10, 0, 0)

    # --> Midday = 1000-1600
    midStart = datetime.time(10, 0, 1)
    midEnd = datetime.time(16, 0, 0)

    # --> Evening = 1600-2200
    eveStart = datetime.time(16, 0, 1)
    eveEnd = datetime.time(22, 0, 0)

    # --> Late Night = 2200-0400
    lateStart = datetime.time(22, 0, 1)
    lateEnd = datetime.time(4, 0, 0)

    if time_in_range(mornStart, mornEnd, ts):
      timecat = 0 #morning
    elif time_in_range(midStart, midEnd, ts):
      timecat = 1 #midday
    elif time_in_range(eveStart, eveEnd, ts):
      timecat = 2 #evening
    elif time_in_range(lateStart, lateEnd, ts):
      timecat = 3 #late night

    return timecat

就是这样,我收到这个错误:

TypeError: argument must be 9-item sequence, not datetime.datetime

当我将相关行更改为:

str_time = time.strptime(Datetime, "%m/%j/%y %H:%M")

我收到此错误:

TypeError: descriptor 'time' requires a 'datetime.datetime' object but received a 'int'

我知道我正在使用两个不同的库或诸如此类的东西,但是我不确定如何在它们之间进行转换或者只使用一个来完成我想做的事情.我只是想让它忽略日期,只检查时间是否在指定的范围内.由于我在代码中的其他地方使用的库,Python 2.6是必须的.

Answer 1

这一行:

str_time = datetime.strptime(Datetime, "%m/%j/%y %H:%M")

根据文档返回一个datetime对象.

您可以通过在解释器中以交互方式运行以下命令来自行测试:

>>> import datetime
>>> datetime.datetime.strptime('12/31/13 00:12', "%m/%j/%y %H:%M")
datetime.datetime(2013, 1, 31, 0, 12)
>>>

然后可以使用该.time()方法访问返回的日期时间的时间部分.

>>> datetime.datetime.strptime('12/31/13 00:12', "%m/%j/%y %H:%M").time()
datetime.time(0, 12)
>>>

datetime.time()然后可以将结果用于您的时间比较.

Answer 2

使用它只会给你时间。

from datetime import datetime

now = datetime.now()
current_time = now.strftime("%H:%M:%S")
print("Current Time =", current_time)