use*_*960 2 linux awk text sed dropbox
文件:
/home/USER/DIR/a
http://www.here.is.a.hyper.link.net/
/home/USER/DIR/b
http://www.here.is.another.hyper.link.net/
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需要删除此文件中的所有奇数行(PUBLIC-DIRECTORY-LIST)?它是我的批处理脚本,可以在下面找到(dropbox batch puburl creator):
for PATH in `cat LIST`
do
echo $PATH
dropbox puburl $PATH
done > PUBLIC-DIRECTORY-LIST
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我是否只是PUBLIC-DIRECTORY-LIST在脚本末尾附加修剪命令?
gho*_*g74 10
# awk 'NR%2==0' file
http://www.here.is.a.hyper.link.net/
http://www.here.is.another.hyper.link.net/
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