use*_*ane 6 java arrays sorting
我有原始阵列
public static void main (String[] arg) {
int[] array = {1,5,6,8,4,2}
for (int i = 0; i < array.length; i++) {
System.out.print("List 1 = " + array[i] + ",");
}
swap(array);
for (int i = 0; i < array.length; i++) {
System.out.print("List 2 = "+array[i] + ",");
}
}
private static int swap (int[] list){
Arrays.sort(list);
}
Run Code Online (Sandbox Code Playgroud)
输出是
List 1 = 1,5,6,8,4,2
List 2 = 1,2,4,5,6,8
Run Code Online (Sandbox Code Playgroud)
我想要的答案是
List 1 = 1,5,6,8,4,2
List 2 = 1,5,6,8,4,2
Run Code Online (Sandbox Code Playgroud)
甚至在分拣后.我该怎么做?
Juv*_*nis 19
int[] originalArray = {1,5,6,8,4,2};
int[] backup = Arrays.copyOf(originalArray,originalArray.length);
Arrays.sort(backup);
Run Code Online (Sandbox Code Playgroud)
在执行上面的代码之后,backup变得排序并originalArray保持相同.