如何在MySQL中建立一个连续的组？

Question

如何在MySQL中返回实际上是"连续"GROUP BY的内容.换句话说,GROUP BY尊重记录集的顺序？

例如,SELECT MIN(col1), col2, COUNT(*) FROM table GROUP BY col2 ORDER BY col1从下表中col1是唯一的有序索引:

1    a
2    a
3    b
4    b
5    a
6    a

收益:

1    a    4
3    b    2

但我需要返回以下内容:

1    a    2
3    b    2
5    a    2

Answer 1

使用:

   SELECT MIN(t.id) 'mi', 
          t.val, 
          COUNT(*)
     FROM (SELECT x.id, 
                 x.val, 
                 CASE 
                   WHEN xt.val IS NULL OR xt.val != x.val THEN 
                     @rownum := @rownum+1 
                   ELSE 
                     @rownum 
                 END AS grp
            FROM TABLE x
            JOIN (SELECT @rownum := 0) r
       LEFT JOIN (SELECT t.id +1 'id',
                         t.val
                    FROM TABLE t) xt ON xt.id = x.id) t
 GROUP BY t.val, t.grp
 ORDER BY mi

这里的关键是创建一个允许分组的人工值.

以前,纠正了Guffa的回答:

   SELECT t.id, t.val
     FROM TABLE t
LEFT JOIN TABLE t2 on t2.id + 1 = t.id
    WHERE t2.val IS NULL 
       OR t.val <> t2.val