Bul*_*ula 5 python beautifulsoup
例如
bs = BeautifulSoup("<html><a>sometext</a></html>")
print bs.find_all("a",text=re.compile(r"some"))
返回[<a>sometext</a>],但当搜索的元素有一个孩子,即img
bs = BeautifulSoup("<html><a>sometext<img /></a></html>")
print bs.find_all("a",text=re.compile(r"some"))
它返回 []
有没有办法用来find_all匹配后面的例子？
Nat*_*usa 14
您将需要使用混合方法,因为text=当元素具有子元素和文本时将失败.
bs = BeautifulSoup("<html><a>sometext</a></html>")
reg = re.compile(r'some')
elements = [e for e in bs.find_all('a') if reg.match(e.text)]
当BeautifulSoup搜索元素并且text是可调用的时,它最终会调用:
self._matches(found.string, self.text)
在您给出的两个示例中,该.string方法返回不同的内容:
>>> bs1 = BeautifulSoup("<html><a>sometext</a></html>")
>>> bs1.find('a').string
u'sometext'
>>> bs2 = BeautifulSoup("<html><a>sometext<img /></a></html>")
>>> bs2.find('a').string
>>> print bs2.find('a').string
None
该.string方法如下所示:
@property
def string(self):
"""Convenience property to get the single string within this tag.
:Return: If this tag has a single string child, return value
is that string. If this tag has no children, or more than one
child, return value is None. If this tag has one child tag,
return value is the 'string' attribute of the child tag,
recursively.
"""
if len(self.contents) != 1:
return None
child = self.contents[0]
if isinstance(child, NavigableString):
return child
return child.string
如果我们打印出内容,我们可以看到为什么会返回None:
>>> print bs1.find('a').contents
[u'sometext']
>>> print bs2.find('a').contents
[u'sometext', <img/>]
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