打破while循环功能？

Question

我正在尝试创建一个包含if/elif语句的函数,我希望if打破一个while循环..该函数用于文本冒险游戏,是一个是/否的问题.这是我到目前为止所提出的......

def yn(x, f, g):
    if (x) == 'y':
         print (f)
         break
    elif (x) == 'n'
         print (g)

name = raw_input('What is your name, adventurer? ')
print 'Nice to meet you, '+name+'. Are you ready for your adventure?'

while True:
    ready = raw_input('y/n ')
    yn(ready, 'Good, let\'s start our adventure!', 
       'That is a real shame.. Maybe next time')

现在我不确定我是否正在使用该功能,但是当我尝试它时,它说我不能在功能上中断.因此,如果有人可以帮助我解决这个问题,如果你能帮助我,如果函数和调用函数本身的格式错误,那将非常感激.

Answer 1

您可以使用例外:

class AdventureDone(Exception): pass

def yn(x, f, g):
    if x == 'y':
         print(f)
    elif x == 'n':
         print(g)
         raise AdventureDone

name = raw_input('What is your name, adventurer? ')
print 'Nice to meet you, '+name+'. Are you ready for your adventure?'

try:
    while True:
        ready = raw_input('y/n ')
        yn(ready, "Good, let's start our adventure!",
           'That is a real shame.. Maybe next time')
except AdventureDone:
    pass
    # or print "Goodbye." if you want

这会循环while遍历循环,但在yn()函数内部会引发异常,从而打破循环.为了不打印回溯,必须捕获并处理异常.

Answer 2

您需要在循环本身中跳出 while 循环，而不是从另一个函数中跳出。

像下面这样的东西可能更接近你想要的：

def yn(x, f, g):
    if (x) == 'y':
        print (f)
        return False
    elif (x) == 'n':
        print (g)
        return True

name = raw_input('What is your name, adventurer? ')
print 'Nice to meet you, '+name+'. Are you ready for your adventure?'

while True:
    ready = raw_input('y/n: ')
    if (yn(ready, 'Good, let\'s start our adventure!', 'That is a real shame.. Maybe next time')):
        break