PyQt窗口在打开后立即关闭

pep*_*etd 5 python pyqt4

大家好.我在尝试打开PyQt窗口时遇到问题.

下面的代码是我原始代码的示例.当我导入import Test并运行模块时test.Start(),我收到以下错误:

QCoreApplication :: exec:事件循环已在运行

经过一些研究,我发现这是因为我已经做了一个QApplication.

test.py....
import sys

def Start():
    app = QApplication(sys.argv)
    m = myWindow()
    m.show()
    app.exec_()

class myWindow():....

if __name__ == "__main__":
    Start()
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那么我读到我可以像这样重写我的代码,它会修复错误:

test.py....

def Start():
    m = myWindow()
    m.show()


class myWindow():....

if __name__ == "__main__":
    import sys
    app = QApplication(sys.argv)
    Start()
    app.exec_()
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现在我不再获得QCoreApplication :: exec:事件循环已经运行错误,但我的窗口在打开后几乎立即关闭.

mat*_*ata 14

你需要保持对打开的窗口的引用,否则它会超出范围并被垃圾收集,这也会破坏底层的C++对象.尝试:

def Start():
    m = myWindow()
    m.show()
    return m


class myWindow():....

if __name__ == "__main__":
    import sys
    app = QApplication(sys.argv)
    window = Start()
    app.exec_()
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Jos*_*osh 5

您也可以:

def Start():
    global m
    m = myWindow()
    m.show()

class myWindow():....

if __name__ == "__main__":
    import sys
    app = QApplication(sys.argv)
    window = Start()
    app.exec_()
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