ListView行号没有绑定

Question

我一直想知道在WPF中是否可以创建一个ListView没有绑定到IEnumerable<>索引属性的行号？也许制作一个自动增加行号的模板？如何实现？

在某些情况下它可能很有用(例如,当您使用以令人不愉快的形式返回大量数据的外部类时 - 如字典或某些自定义类).

Answer 1

XAML:

  <ListView.View>
     <GridView>
        <!-- This is the column where the row index is to be shown -->
        <GridViewColumn Width="100" Header="No."
        DisplayMemberBinding="{Binding RelativeSource=
             {RelativeSource FindAncestor, AncestorType={x:Type ListViewItem}}, 
              Converter={StaticResource IndexConverter}}" />
        <!-- other columns, may be bound to your viewmodel instance -->
        <GridViewColumn Width="100"
        ...
        </GridViewColumn>
    </GridView>
  </ListView.View>

创建转换器类:

public class IndexConverter : IValueConverter
{
    public object Convert(object value, Type TargetType, object parameter, CultureInfo culture)
    {
        var item = (ListViewItem) value;
        var listView = ItemsControl.ItemsControlFromItemContainer(item) as ListView;
        int index = listView.ItemContainerGenerator.IndexFromContainer(item) + 1;
        return index.ToString();
    }

    public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
    {
        throw new NotImplementedException();
    }
}

在窗口或控件的资源部分:

<Converter:IndexConverter x:Key="IndexConverter" />