这个查询不起作用的原因是什么?如果我只是排除WHERE子句,以下查询将起作用.我需要知道它有什么问题.我知道表中存在$ key的给定值,为什么这不起作用?
$q = "SELECT * WHERE t1.project=$key
FROM project_technologies AS t1
JOIN languages AS t2
ON t1.language = t2.key";
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表格包含以下字段:
project_technologies
- 关键
- 项目
- 语言
语言
- 键
- 名称
SELECT * FROM project_technologies AS t1
JOIN languages AS t2
ON t1.language = t2.key
WHERE t1.project=$key
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的where应在结束(JOIN的后)
FROM/JOIN之后的地方.
SELECT *
FROM project_technologies AS t1
JOIN languages AS t2
ON t1.language = t2.key
WHERE t1.project=$key
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小智 5
SELECT *
FROM project_technologies AS t1
JOIN languages AS t2
ON t1.language = t2.key
WHERE t1.project=$key
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