Swa*_*ukh 12 android android-viewpager
我在我的activity中使用了view pager.我创建了7页的视图.现在我想访问我的活动中的页面视图.我将数据视为空白. 在活动中
public class ActivitySingleEntry extends Activity implements OnClickListener {
private ViewPager mPager;
private FixedTabsView mFixedTabs;
private ExamplePagerAdapter mPagerAdapter;
private TabsAdapter mFixedTabsAdapter;
private EditText edtFieldName;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_fixed_tabs);
initViewPager(7, 0xFFFFFFFF, 0xFF000000);
mFixedTabs = (FixedTabsView) findViewById(R.id.fixed_tabs);
mFixedTabsAdapter = new FixedTabsAdapter(this);
mFixedTabs.setAdapter(mFixedTabsAdapter);
mFixedTabs.setViewPager(mPager);
}
private void initViewPager(int pageCount, int backgroundColor, int textColor) {
mPager = (ViewPager) findViewById(R.id.pager);
mPagerAdapter = new ExamplePagerAdapter(this, pageCount,
backgroundColor, textColor);
mPager.setAdapter(mPagerAdapter);
mPager.setCurrentItem(1);
mPager.setPageMargin(5);
}
@Override
public void onClick(View v) {
// LinearLayout lin=(LinearLayout) mPager.getChildAt(mPager.getCurrentItem());
// edtFieldName=(EditText) lin.findViewById(R.id.edtFieldName);
// Log.d("test", "From get child:"+edtFieldName.getText().toString()+":");
Log.d("test", "Current Page:"+mPager.getCurrentItem());
LinearLayout linearLayout=(LinearLayout) mPager.findViewWithTag("lin"+mPager.getCurrentItem());
edtFieldName=(EditText) linearLayout.findViewById(R.id.edtFieldName);
edtFieldName=(EditText) findViewById(R.id.edtFieldName);
if (edtFieldName==null) {
ShowToast.makeToast(getApplicationContext(), "Edt null");
}else
ShowToast.makeToast(getApplicationContext(),
"Data saved " + edtFieldName.getText().toString() + ":"
+ mPager.getCurrentItem());
}
}
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我的PageAdaper
public class ExamplePagerAdapter extends PagerAdapter {
protected transient Activity mContext;
private int mLength = 0;
private int mBackgroundColor = 0xFFFFFFFF;
private int mTextColor = 0xFF000000;
private String[] mData = { "Temperature", "Sugar", "BP", "Field 4",
"Field 5", "Field 6", "Field 7" };
public ExamplePagerAdapter(Activity context, int length,
int backgroundColor, int textColor) {
mContext = context;
mLength = length;
mBackgroundColor = backgroundColor;
mTextColor = textColor;
}
@Override
public int getCount() {
return mLength;
}
@Override
public Object instantiateItem(View container, int position) {
LinearLayout linearLayout = (LinearLayout) View.inflate(mContext,
R.layout.activity_single_entry, null);
TextView txtFieldName = (TextView) linearLayout
.findViewById(R.id.txtFieldName);
EditText edtFieldName = (EditText) linearLayout
.findViewById(R.id.edtFieldName);
String filedName = mData[position];
txtFieldName.setText(filedName);
edtFieldName.setHint("Please enter " + filedName);
edtFieldName.setInputType(InputType.TYPE_CLASS_TEXT);
if (filedName.equals("Temperature")) {
edtFieldName.setInputType(InputType.TYPE_CLASS_NUMBER);
} else if (filedName.equals("Sugar")) {
edtFieldName.setInputType(InputType.TYPE_CLASS_NUMBER);
} else if (filedName.equals("BP")) {
edtFieldName.setInputType(InputType.TYPE_CLASS_NUMBER);
}
edtFieldName.setTag("edt");
((ViewPager) container).addView(linearLayout, 0);
linearLayout.setTag("lin"+position);
Log.d("test", "Adapter creating item:"+position );
return linearLayout;
}
@Override
public void destroyItem(View container, int position, Object view) {
((ViewPager) container).removeView((View) view);
}
@Override
public boolean isViewFromObject(View view, Object object) {
return view == ((View) object);
}
@Override
public void finishUpdate(View container) {
}
@Override
public void restoreState(Parcelable state, ClassLoader loader) {
}
@Override
public Parcelable saveState() {
return null;
}
@Override
public void startUpdate(View container) {
}
}
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在R.layout.activity_single_entry xml中我有带有onclick的edittext和按钮.
MYXml
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content" >
<TextView
android:id="@+id/txtFieldName"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="TextView" />
<EditText
android:id="@+id/edtFieldName"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginLeft="10dp"
android:layout_weight="1"
android:hint="Please enter field value" />
</LinearLayout>
<Button
android:id="@+id/btnSave"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="Save"
android:layout_margin="20dp"
android:onClick="onClick"
/>
</LinearLayout>
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如果我在pageadapter中使用
@Override
public int getItemPosition(Object object) {
// TODO Auto-generated method stub
return POSITION_NONE;
}
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单击按钮我想从编辑文本访问数据.
我能够获得第一页的价值.不是所有人.
psk*_*ink 10
首先你setTag():
linearLayout.setTag("lin"+position);
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位置在<0..numPages-1>中
但请阅读:
LinearLayout linearLayout=(LinearLayout) mPager.findViewWithTag("lin"+mPager.getCurrentItem());
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findViewWithTag在任何地方或仅在最后一页返回null?mPager.getCurrentItem()如果是第一页则返回0,因此在读取时不需要添加+1
Mee*_*how -1
一个快速的解决方案是在您的 ExamplePagerAdapter 中保留一个列表,并在 addView() 调用后添加到它。然后,您可以实现一个公共函数,例如 getItemAtPosition(intposition),它返回 ViewPager 的该页面的 LinearLayout。然后,您可以在 Activity 中的线性布局上运行 findViewById(R.id.edtFieldName) 。在代码中:
在您的 ExamplePagerAdapter 中,添加一个私有对象:
List<LinearLayout> mItems;
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添加到你的构造函数中:
mItems = new Vector<LinearLayout>();
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在instantiateItem()中添加:
((ViewPager) container).addView(linearLayout, 0);
mItems.add(linearLayout);
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然后添加一个方法:
public LinearLayout getItemAtPosition(int position) {
return mItems.get(position);
}
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然后在您的活动中使用该方法。希望这是您正在寻找的。
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