til*_*lak 38 javascript jquery number-systems
我在印度编号系统中显示以下代码.
var x=125465778;
var res= x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");
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得到这个输出:125,465,778
.
我需要这样的输出:12,54,65,778
.
请帮我解决这个问题.
Pra*_*h K 52
对于整数:
var x=12345678;
x=x.toString();
var lastThree = x.substring(x.length-3);
var otherNumbers = x.substring(0,x.length-3);
if(otherNumbers != '')
lastThree = ',' + lastThree;
var res = otherNumbers.replace(/\B(?=(\d{2})+(?!\d))/g, ",") + lastThree;
alert(res);
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对于浮动:
var x=12345652457.557;
x=x.toString();
var afterPoint = '';
if(x.indexOf('.') > 0)
afterPoint = x.substring(x.indexOf('.'),x.length);
x = Math.floor(x);
x=x.toString();
var lastThree = x.substring(x.length-3);
var otherNumbers = x.substring(0,x.length-3);
if(otherNumbers != '')
lastThree = ',' + lastThree;
var res = otherNumbers.replace(/\B(?=(\d{2})+(?!\d))/g, ",") + lastThree + afterPoint;
alert(res);
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Tus*_*har 43
我迟到但我想这会有所帮助:)
你可以使用Number.prototype.toLocaleString()
句法
numObj.toLocaleString([locales [, options]])
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var number = 123456.789;
// India uses thousands/lakh/crore separators
document.getElementById('result').innerHTML = number.toLocaleString('en-IN');
// ? 1,23,456.789
document.getElementById('result1').innerHTML = number.toLocaleString('en-IN', {
maximumFractionDigits: 2,
style: 'currency',
currency: 'INR'
});
// ? Rs.123,456.79
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<div id="result"></div>
<div id="result1"></div>
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slo*_*pen 18
对于整数,只需要不需要额外的操作.
这将匹配末尾的每个数字,后面有一个或多个双位数字模式,并将其替换为自身+",":
"125465778".replace(/(\d)(?=(\d\d)+$)/g, "$1,");
-> "1,25,46,57,78"
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但是因为我们想要最后有3个,所以让我们通过在输入的匹配结束之前添加额外的"\ d"来明确说明:
"125465778".replace(/(\d)(?=(\d\d)+\d$)/g, "$1,");
-> "12,54,65,778"
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简单的方法,
1.使用LocalString()的直接方法
(1000.03).toLocaleString()
(1000.03).toLocaleString('en-IN') # number followed by method
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2.使用Intl-国际化API
Intl对象是ECMAScript国际化API的命名空间,该API提供语言敏感的字符串比较,数字格式以及日期和时间格式。
例如: Intl.NumberFormat('en-IN').format(1000)
3.使用自定义功能:
(1000.03).toLocaleString()
(1000.03).toLocaleString('en-IN') # number followed by method
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如果您输入的是10000.5,
numberWithCommas(10000.5)
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您将得到这样的输出, 10,000.5
给定一个低于函数的数字,它返回印度格式的数字分组的格式化数字.
例如:输入:12345678567545.122343
输出:1,23,45,67,85,67,545.122343
function formatNumber(num) {
var n1, n2;
num = num + '' || '';
// works for integer and floating as well
n1 = num.split('.');
n2 = n1[1] || null;
n1 = n1[0].replace(/(\d)(?=(\d\d)+\d$)/g, "$1,");
num = n2 ? n1 + '.' + n2 : n1;
return num;
}
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https://jsfiddle.net/scLtnug8/1/
我在比赛中有点晚了。但这是执行此操作的隐式方法。
var number = 3493423.34;
console.log(new Intl.NumberFormat('en-IN', { style: "currency", currency: "INR" }).format(number));
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如果您不想要货币符号,请像这样使用它
console.log(new Intl.NumberFormat('en-IN').format(number));
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