Tyl*_*ler 6 asp.net-mvc ajax.beginform drop-down-menu
码:
<% using (Ajax.BeginForm("GetResourcesByProject", "CreateRequest", new AjaxOptions { UpdateTargetId = "ResourceListDiv"}))
{
Response.Write(Html.DropDownList("SelectProject", Model.ProjectList, "Select Project", new { onchange = "this.form.submit();" }));
} %>
Run Code Online (Sandbox Code Playgroud)
当我运行页面时,我得到正确的控制器操作,以使用表单集合中的正确数据进行触发:
public ActionResult GetResourcesByProject(FormCollection formCollection)
{
var resourceModels = (from project in POTSModel.ProjectList
where project.Id == Convert.ToInt32(formCollection["SelectProject"])
select project).First().Resources;
return PartialView("ResourceList", resourceModels);
}
Run Code Online (Sandbox Code Playgroud)
它从Ajax.ActionLink可以正常工作,如下所示:
<%= Ajax.ActionLink("Select", "GetResourcesByProject", "CreateRequest", new { projectId = item.Id }, new AjaxOptions { UpdateTargetId = "ResourceListDiv" })%>
Run Code Online (Sandbox Code Playgroud)
当帖子发生时,我将导航到新页面,而不是停留在现有页面上并更新div的内容.
谢谢.
submit()可能不会触发Ajax.BeginForm,因此它会像往常一样处理.请参阅此示例:提交我的Ajax.BeginForm的其他jQuery事件.或者添加提交按钮(可能隐藏)并调用其.click().
| 归档时间: |
|
| 查看次数: |
12029 次 |
| 最近记录: |