基于值拆分数组

Question

自从我不得不处理一些javascript代码以来,已经很长时间了,我生气了.

我需要像这样分割一个数组:

Object (
    [0] => 2013-04-12
    [1] => text
    [2] => text
    [3] => text
    [4] => text
    [5] => 2013-04-11
    [6] => text
    [7] => text
    [8] => text
    [9] => text
    [10] => text
    [11] => text
    [12] => 2013-04-10
    [13] => text
    [14] => text
    [15] => text
    [16] => text
    [17] => 2013-04-09
    [18] => text
    [19] => text
    [20] => text
)

到json对象或数组,其中索引0始终是日期:

Object0 (
    [0] => 2013-04-12
    [1] => text
    [2] => text
    [3] => text
    [4] => text
)
Object1 (
    [0] => 2013-04-11
    [1] => text
    [2] => text
    [3] => text
    [4] => text
    [5] => text
    [6] => text
)

Object2 (
    [0] => 2013-04-10
    [1] => text
    [2] => text
    [3] => text
    [4] => text
)

Object3 (
    [0] => 2013-04-09
    [1] => text
    [2] => text
    [3] => text
)

正如您所看到的,我只能使用该值来计算出每个新数组,这些数组可能具有不同的大小.

谢谢你的帮助.

更新 对不起,我没有在最初的问题中发布我的代码,因为我写的东西太废了(我感到非常惭愧).这里我使用的代码归功于Bangerang的解决方案.感谢大家的帮助和贡献.

var events = [];
var result = [];
var j = 0;
for (var i = 0; i < tableData.length; i++){
    if (/^(\d{4})-(\d{2})-(\d{2})$/.test(tableData[i])){ //Returning true if it's just numbers
        j = j + 1;
        events[j] = [];
        events[j].push(tableData[i]);
        result.push(events[j]);
    } else {
        events[j].push(tableData[i]);
    }
}

// Then I write the json message which will be eval to use with FullCalendar.
var json_events = '[';
for (var i = 1; i <= events.length; i++){
    if (typeof events[i] !== 'undefined' && events[i].length > 0) {
        for (var j = 0; j < events[i].length; j++){
            if(/@/.test(events[i][j])){

                json_events += '{"start":"' + events[i][0] + '",';
                json_events += '"textColor":"black",';

                var tmp = events[i][j].split("@");
                json_events += '"backgroundColor":"' + tmp[0] + '",';

                var text_pattern = new RegExp(/<b>([a-z_]+)<\/b>(.+)/);
                var title_desc = text_pattern.exec(tmp[1]);                            
                json_events += '"title":"' + title_desc[1] + '",';
                json_events += '"description":"' + title_desc[0] + '"';
                json_events += '},';
            }
        }
    }
}
json_events += ']';
json_events = json_events.replace("},]","}]"); 

Answer 1

假设日期是唯一只有数字的日期,你可以试试这个:

var object = [];
var result = [];
for (var i = 0; i < objects.length; i++){
    if (/^\d+$/.test(objects[i])){ //Returning true if it's just numbers
        object = []
        object.push(objects[i]);
        result.push(object);
    }else {
        object.push(objects[i]);
    }
}