我有两个CSV文件代表两个不同年份的数据.我知道如何使用csvwriter和dictkeys进行基本合并,但问题在于:虽然CSV主要是共享列标题,但每个列可能都有唯一的列.如果一个物种在一年内被捕获而不是另一个物种捕获,则该列仅在那一年出现.如何将新数据合并到旧数据,创建新列并在这些列中填零旧数据?
档案1: "Date","Time","Species A","Species B", "Species X"
文件2: "Date","Time", "Species A", "Species B", "Species C"
我需要最终结果是这个标题的一个csv:"Date","Time","Species A","Species B", "Species C", "Species X"
其他人可能会使用该csv模块发布一个解决方案,所以我会给出一个熊猫解决方案用于比较目的:
import pandas as pd
df1 = pd.read_csv("fish1.csv")
df2 = pd.read_csv("fish2.csv")
df = pd.concat([df1, df2]).fillna(0)
df = df[["Date", "Time"] + list(df.columns[1:-1])]
df.to_csv("merged_fish.csv", index=False)
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说明:
首先,我们读入两个文件:
>>> df1 = pd.read_csv("fish1.csv")
>>> df2 = pd.read_csv("fish2.csv")
>>> df1
Date Time Species A Species B Species X
0 1 2 3 4 5
1 6 7 8 9 10
2 11 12 13 14 15
>>> df2
Date Time Species A Species B Species C
0 16 17 18 19 20
1 21 22 23 24 25
2 26 27 28 29 30
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然后我们简单地连接它们,它自动填充缺少的数据NaN:
>>> df = pd.concat([df1, df2])
>>> df
Date Species A Species B Species C Species X Time
0 1 3 4 NaN 5 2
1 6 8 9 NaN 10 7
2 11 13 14 NaN 15 12
0 16 18 19 20 NaN 17
1 21 23 24 25 NaN 22
2 26 28 29 30 NaN 27
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你希望它们用0填充,所以:
>>> df = pd.concat([df1, df2]).fillna(0)
>>> df
Date Species A Species B Species C Species X Time
0 1 3 4 0 5 2
1 6 8 9 0 10 7
2 11 13 14 0 15 12
0 16 18 19 20 0 17
1 21 23 24 25 0 22
2 26 28 29 30 0 27
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这个顺序是不太你问了一个,不过,你想Time和Date第一,所以:
>>> df = df[["Date", "Time"] + list(df.columns[1:-1])]
>>> df
Date Time Species A Species B Species C Species X
0 1 2 3 4 0 5
1 6 7 8 9 0 10
2 11 12 13 14 0 15
0 16 17 18 19 20 0
1 21 22 23 24 25 0
2 26 27 28 29 30 0
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然后我们将其保存为CSV文件:
>>> df.to_csv("merged_fish.csv", index=False)
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生产
Date,Time,Species A,Species B,Species C,Species X
1,2,3,4,0.0,5.0
6,7,8,9,0.0,10.0
11,12,13,14,0.0,15.0
16,17,18,19,20.0,0.0
21,22,23,24,25.0,0.0
26,27,28,29,30.0,0.0
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