从NSMutableArray中删除对象？

Question

我在ViewDidLoad方法中有一个包含以下元素的数组

inputArray = [NSMutableArray arrayWithObjects:@"car", @"bus", @"helicopter", @"cruiz", @"bike", @"jeep", nil];

我还有一个UITextField用于搜索的元素.所以一旦我输入一些东西UITextField,我想检查该字符串是否存在"inputArray"或not.If它不与inputArray元素匹配然后从inputArray相应的元素.

 for (NSString* item in inputArray)
   {
        if ([item rangeOfString:s].location == NSNotFound) 
        {
            [inputArray removeObjectIdenticalTo:item];//--> Shows Exception
            NSLog(@"Contains :%@",containsAnother);
        }

  }

但此代码显示异常,与"removeobject:"相关的内容

例外:

Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[__NSCFConstantString rangeOfString:options:range:locale:]: nil argument'
*** First throw call stack:
`

Answer 1

In fast enumeration you can NOT modify the collection.

The enumerator object becomes constant and immutable.

If you want to do updation on the array

You should like this :

NSMutableArray *inputArray = [NSMutableArray arrayWithObjects:@"car", @"bus", @"helicopter", @"cruiz", @"bike", @"jeep", nil];
NSString *s=@"bus";

for (int i=inputArray.count-1; i>-1; i--) {
    NSString *item = [inputArray objectAtIndex:i];
    if ([item rangeOfString:s].location == NSNotFound) {
        [inputArray removeObject:item];
    }
}

EDIT:

The above works similar as this :

NSArray *array=[inputArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"SELF CONTAINS[c] %@",s]]; 

Answer 2

您可以使用以下代码

for (int i=0;i<[inputArray count]; i++) {
        NSString *item = [inputArray objectAtIndex:i];
        if ([item rangeOfString:s].location == NSNotFound) {
            [inputArray removeObject:item];
            i--;
        }
    }