Cri*_*usa 3 java assertions quantifiers smt z3
Z3中是否有办法证明/显示给定模型是唯一的,并且不存在其他解决方案?
一个小例子来演示
(declare-const a1 Int)
(declare-const a2 Int)
(declare-const a3 Int)
(declare-const b1 Int)
(declare-const b2 Int)
(declare-const b3 Int)
(declare-const c1 Int)
(declare-const c2 Int)
(declare-const c3 Int)
(declare-const ra Int)
(declare-const rb Int)
(declare-const rc Int)
(declare-const r1 Int)
(declare-const r2 Int)
(declare-const r3 Int)
(assert (>= a1 0))
(assert (>= a2 0))
(assert (>= a3 0))
(assert (>= b1 0))
(assert (>= b2 0))
(assert (>= b3 0))
(assert (>= c1 0))
(assert (>= c2 0))
(assert (>= c3 0))
(assert (<= a1 9))
(assert (<= a2 9))
(assert (<= a3 9))
(assert (<= b1 9))
(assert (<= b2 9))
(assert (<= b3 9))
(assert (<= c1 9))
(assert (<= c2 9))
(assert (<= c3 9))
(assert (= ra 38))
(assert (= rb 1))
(assert (= rc 27))
(assert (= r1 55))
(assert (= r2 72))
(assert (= r3 6))
(assert (= ra (- (* a1 a2) a3)))
(assert (= rb (- (- b1 b2) b3)))
(assert (= rc (* (* c1 c2) c3)))
(assert (= r1 (- (* a1 b1) c1)))
(assert (= r2 (* (+ a2 b2) c2)))
(assert (= r3 (- (+ a3 b3) c3)))
(check-sat)
(get-model)
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我知道以下模型是唯一的事实,但是我可以使用某些Z3选项或添加断言来确保这一点吗?
(model
(define-fun c3 () Int
3)
(define-fun c2 () Int
9)
(define-fun c1 () Int
1)
(define-fun b3 () Int
5)
(define-fun b2 () Int
2)
(define-fun b1 () Int
8)
(define-fun a3 () Int
4)
(define-fun a2 () Int
6)
(define-fun a1 () Int
7)
(define-fun r3 () Int
6)
(define-fun r2 () Int
72)
(define-fun r1 () Int
55)
(define-fun rc () Int
27)
(define-fun rb () Int
1)
(define-fun ra () Int
38)
)
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为了澄清起见,我通过de JAVA API使用Z3
是的:想法是断言所找到的模型分配的值是唯一可能的分配,因此它是唯一的。这可以通过添加一个声明来完成,该声明声明所有常量都不等于为其分配的模型值。
对于您的示例,这将是:
(assert (not (and
(= c3 3)
(= c2 9)
(= c1 1)
(= b3 5)
(= b2 2)
(= b1 8)
(= a3 4)
(= a2 6)
(= a1 7)
(= r3 6)
(= r2 72)
(= r1 55)
(= rc 27)
(= rb 1)
(= ra 38))))
(check-sat) ; unsat => no other model exists
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如果尝试更改任何值(例如,将c3 = 3更改为c3 = 4),这将再次变得令人满意。这是指向完整示例的rise @ fun链接:http : //rise4fun.com/Z3/nD5n
有关如何使用API以编程方式执行此操作的更多详细信息,请参阅以下问题和解答:
请注意,根据第二个链接的答案中的注释,您不能仅使用SMT-lib前端以编程方式执行此操作,如果要自动执行此过程,则必须使用API遍历找到的模型。
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