Iva*_*nov 5 sql oracle oracle10g union-all
我有一个SQL查询具有完全相同的代码,但有两个不同的表(AUDIT_TRAIL_ARCHIVE和AUDIT_TRAIL).我使用"UNION ALL"来获得一个结果.
优秀的程序员使用"不要重复自己"的原则.优秀的程序员避免WET(写两次).
如何用"不要重复自己"的原则重写这段代码?
SELECT REPLACE (ENTITY_KEY, 'rss_user_name=CN=', '')
FROM AUDIT_TRAIL_ARCHIVE AU
INNER JOIN
(SELECT RSS_USER_NAME
FROM RSS_USER
WHERE RSS_NAME = 'rmad'
AND ADD_INFO_MASTER LIKE '%__47__UPN=%@richemont.com%') FALSCH
ON REPLACE (AU.ENTITY_KEY, 'rss_user_name=CN=', '') =
FALSCH.RSS_USER_NAME
WHERE AU.RSS_NAME = 'rmad'
AND AU.TABLE_NAME = 'rss_user'
AND AU.ACTION = 'Insert'
AND AU.ENTITY_KEY LIKE 'rss_user_name=CN=%'
AND AU.ORIGIN != 'RSS'
UNION ALL
SELECT REPLACE (ENTITY_KEY, 'rss_user_name=CN=', '')
FROM AUDIT_TRAIL AU
INNER JOIN
(SELECT RSS_USER_NAME
FROM RSS_USER
WHERE RSS_NAME = 'rmad'
AND ADD_INFO_MASTER LIKE '%__47__UPN=%@richemont.com%') FALSCH
ON REPLACE (AU.ENTITY_KEY, 'rss_user_name=CN=', '') =
FALSCH.RSS_USER_NAME
WHERE AU.RSS_NAME = 'rmad'
AND AU.TABLE_NAME = 'rss_user'
AND AU.ACTION = 'Insert'
AND AU.ENTITY_KEY LIKE 'rss_user_name=CN=%'
AND AU.ORIGIN != 'RSS'
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例如:
SELECT REPLACE (ENTITY_KEY, 'rss_user_name=CN=', '')
FROM (select * --or relevant columns
from AUDIT_TRAIL_ARCHIVE AU
union all
select *
from AUDIT_TRAIL AU
) AU
INNER JOIN
(SELECT RSS_USER_NAME
FROM RSS_USER
WHERE RSS_NAME = 'rmad'
AND ADD_INFO_MASTER LIKE '%__47__UPN=%@richemont.com%') FALSCH
ON REPLACE (AU.ENTITY_KEY, 'rss_user_name=CN=', '') =
FALSCH.RSS_USER_NAME
WHERE AU.RSS_NAME = 'rmad'
AND AU.TABLE_NAME = 'rss_user'
AND AU.ACTION = 'Insert'
AND AU.ENTITY_KEY LIKE 'rss_user_name=CN=%'
AND AU.ORIGIN != 'RSS'
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