Objective-C + JSON解析Google Places API的objectForKey

Dav*_*iri 2 xcode parsing json objective-c ios

我有这个:

    //request stuff
NSString *searchString = [NSString stringWithFormat:@"Sydney"];
NSString *urlString = [NSString stringWithFormat:@"https://maps.googleapis.com/maps/api/place/textsearch/json?query=%@&sensor=true&key=mykeynotyours!",searchString];

NSURL *requestURL = [NSURL URLWithString:urlString];
NSURLRequest *request = [NSURLRequest requestWithURL:(requestURL)];

//response
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSError *jsonParsingError = nil;
NSDictionary *locationResults = [NSJSONSerialization JSONObjectWithData:response options:0 error:&jsonParsingError];

NSLog(@"%@",locationResults);
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哪个是吐出一些结果,第一个是我想要的结果,但我不能像其他API一样得到lat和lng说:

NSString *stringLatitude = [locationResults objectForKey:@"lat"];
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我怀疑它正在寻找的关键是"结果"键的一个子集,我不知道如何告诉它:-(

结果:

    2013-04-12 18:47:49.784 Test[26984:c07] {
"html_attributions" =     (
);
results =     (
            {
        "formatted_address" = "Sydney NSW, Australia";
        geometry =             {
            location =                 {
                lat = "-33.8674869";
                lng = "151.2069902";
            };
            viewport =                 {
                northeast =                     {
                    lat = "-33.4245981";
                    lng = "151.3426361";
                };
                southwest =                     {
                    lat = "-34.1692489";
                    lng = "150.502229";
                };
            };
        };
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感谢任何指导!

Dip*_*ara 5

您可以使用以下代码访问几何lat和lang

NSString *stringLatitude = [[[[[locationResults objectForKey:@"results"] objectAtIndex:0] objectForKey:@"geometry"] objectForKey:@"location"] valueForKey:@"lat"];
NSString *stringLongitude = [[[[[locationResults objectForKey:@"results"] objectAtIndex:0] objectForKey:@"geometry"] objectForKey:@"location"] valueForKey:@"lng"];
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