如何交换?的第一个和最后一个元素ArrayList
?我知道如何交换数组的元素:设置一个临时值来存储第一个元素,让第一个元素等于最后一个元素,然后让最后一个元素等于存储的第一个元素.
int a = values[0];
int n = values.length;
values[0] = values[n-1];
values[n-1] = a;
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那么ArrayList<String>
它会是这样的吗?
String a = words.get(0);
int n = words.size();
words.get(0) = words.get(n-1);
words.get(n-1) = a
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nee*_*vek 14
在Java中,你不能通过赋值给ArrayList中的值来设置一个set()
方法来调用:
String a = words.get(0);
words.set(0, words.get(words.size() - 1));
words.set(words.size() - 1, a)
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Nik*_*wal 11
像这样使用.这是代码的在线编译.看看http://ideone.com/MJJwtc
public static void swap(List list,
int i,
int j)
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交换指定列表中指定位置的元素.(如果指定的位置相等,则调用此方法会使列表保持不变.)
参数:list - 要交换元素的列表.i - 要交换的一个元素的索引.j - 要交换的其他元素的索引.
阅读官方收藏文件
import java.util.*;
import java.lang.*;
class Main {
public static void main(String[] args) throws java.lang.Exception
{
//create an ArrayList object
ArrayList words = new ArrayList();
//Add elements to Arraylist
words.add("A");
words.add("B");
words.add("C");
words.add("D");
words.add("E");
System.out.println("Before swaping, ArrayList contains : " + words);
/*
To swap elements of Java ArrayList use,
static void swap(List list, int firstElement, int secondElement)
method of Collections class. Where firstElement is the index of first
element to be swapped and secondElement is the index of the second element
to be swapped.
If the specified positions are equal, list remains unchanged.
Please note that, this method can throw IndexOutOfBoundsException if
any of the index values is not in range. */
Collections.swap(words, 0, words.size() - 1);
System.out.println("After swaping, ArrayList contains : " + words);
}
}
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Oneline编译示例http://ideone.com/MJJwtc
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