非静态变量,不能从静态上下文引用

Joh*_*ith 8 java static non-static

错误来自此行BoardState addme = new BoardState();

由于某种原因,它所指向的非静态变量是"新的".我不清楚如何修复此错误,因为新的并不意味着变量,而不是.

通过stackoverflow记录查看此错误通常来自非静态方法,该方法通常通过使方法静态或完全绕过该方法来解决.Ť

下面的代码用于引用此语句之前和之后发生的事情.

public class IntelligentTicTacToe extends TicTacToe {

public class BoardState{
    public String TTTState;
    public int[][] defensiveOppsArray;
    public int[][] offensiveOppsArray;
    public String str;
    public int cnt;
}

public static ArrayList<BoardState> memory = new ArrayList<BoardState>();


public static boolean makeMove(){
    char[] oArray = new char[TicTacToeArray.length];
    int[][] defensiveOppsArray = new int[TicTacToeArray.length][TicTacToeArray.length];
    int[][] offensiveOppsArray = new int[TicTacToeArray.length][TicTacToeArray.length];
    int[][] sumOppsArray = new int[TicTacToeArray.length][TicTacToeArray.length];
    //converts our Array into a String
    String x = convertTTTArrayToString();

    //Goes through the conditions to see if we have it in memory or if we must go through all the conditions
    boolean matchFound = false;
        for(int i=0; i < memory.size(); i++){
            BoardState element = memory.get(i);
            if(element.str.equals(x)){
                System.out.println("Match Found");
                matchFound = true;
            }}
        if(!matchFound){
        BoardState addme = new BoardState();
        addme.str = x;
        addme.cnt = 1;
        memory.add(addme);

        }
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} ....

Ale*_*ula 18

它不起作用的原因是因为你的类BoardState是一个内部的,非静态的类IntelligentTicTacToe.这意味着在引用它时,您将引用该类的实例; 静态上下文中不提供该实例.

一种解决方案是将该类声明为:

public static class BoardState {
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你可以阅读更多的内部类在这里.