use*_*501 9 python split join punctuation
因此,我尝试join()
在将字符串拆分为单词和标点符号后使用,但它将字符串与单词和标点符号之间的空格连接起来。
b = ['Hello', ',', 'who', 'are', 'you', '?']
c = " ".join(b)
但这会返回:
c = 'Hello , who are you ?'
而且我要:
c = 'Hello, who are you?'
您可以先加入标点符号:
def join_punctuation(seq, characters='.,;?!'):
characters = set(characters)
seq = iter(seq)
current = next(seq)
for nxt in seq:
if nxt in characters:
current += nxt
else:
yield current
current = nxt
yield current
c = ' '.join(join_punctuation(b))
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生成join_punctuation
器生成已加入任何以下标点符号的字符串:
>>> b = ['Hello', ',', 'who', 'are', 'you', '?']
>>> list(join_punctuation(b))
['Hello,', 'who', 'are', 'you?']
>>> ' '.join(join_punctuation(b))
'Hello, who are you?'
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