这是我简单的匿名代码块:
do $$
declare foo varchar(50) := '';
begin
for a in
select a from (values('foo'), ('bar'), ('fooBar')) s(a)
loop
foo := a;
print foo;
end loop;
end;
$$;
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当我运行它:
psql -f test.sql
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我收到此错误:
psql:test.sql:11: ERROR: loop variable of loop over rows must be a record or row variable or list of scalar variables
LINE 4: for a in
^
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Ric*_*nop 67
自己解决了,meh:
do $$
declare
arow record;
foo varchar(50);
begin
for arow in
select a from (values('foo'), ('bar'), ('fooBar')) s(a)
loop
foo := arow.a;
RAISE NOTICE 'Calling cs_create_job(%)', foo;
end loop;
end;
$$;
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