从HttpResponseMessage获取内容/消息

Question

我正在尝试获取HttpResponseMessage的内容.它应该是:{"message":"Action '' does not exist!","success":false}但我不知道如何从HttpResponseMessage中获取它.

HttpClient httpClient = new HttpClient();
HttpResponseMessage response = await httpClient.GetAsync("http://****?action=");
txtBlock.Text = Convert.ToString(response); //wrong!

在这种情况下,txtBlock将具有以下值:

StatusCode: 200, ReasonPhrase: 'OK', Version: 1.1, Content: System.Net.Http.StreamContent, Headers:
{
  Vary: Accept-Encoding
  Keep-Alive: timeout=15, max=100
  Connection: Keep-Alive
  Date: Wed, 10 Apr 2013 20:46:37 GMT
  Server: Apache/2.2.16
  Server: (Debian)
  X-Powered-By: PHP/5.3.3-7+squeeze14
  Content-Length: 55
  Content-Type: text/html
}

Answer 1

我认为最简单的方法就是将最后一行更改为

txtBlock.Text = await response.Content.ReadAsStringAsync(); //right!

这样您就不需要引入任何流读取器,也不需要任何扩展方法.

Answer 2

你需要调用GetResponse().

Stream receiveStream = response.GetResponseStream ();
StreamReader readStream = new StreamReader (receiveStream, Encoding.UTF8);
txtBlock.Text = readStream.ReadToEnd();

Answer 3

试试这个,你可以创建一个像这样的扩展方法:

    public static string ContentToString(this HttpContent httpContent)
    {
        var readAsStringAsync = httpContent.ReadAsStringAsync();
        return readAsStringAsync.Result;
    }

然后,简单地调用扩展方法:

txtBlock.Text = response.Content.ContentToString();

我希望这能帮助你;-)

Answer 4

如果要将其强制转换为特定类型(例如,在测试中),可以使用ReadAsAsync扩展方法:

object yourTypeInstance = await response.Content.ReadAsAsync(typeof(YourType));

或者跟随同步代码:

object yourTypeInstance = response.Content.ReadAsAsync(typeof(YourType)).Result;

更新:还有ReadAsAsync <>的通用选项,它返回特定的类型实例而不是对象声明的实例:

YourType yourTypeInstance = await response.Content.ReadAsAsync<YourType>();

Answer 5

由 rudivonstaden 的回答

txtBlock.Text = await response.Content.ReadAsStringAsync();

但如果你不想使方法异步，你可以使用

txtBlock.Text = response.Content.ReadAsStringAsync();
txtBlock.Text.Wait();

Wait() 很重要，因为我们正在执行异步操作，我们必须等待任务完成才能继续。

Answer 6

我建议的快速答案是：

response.Result.Content.ReadAsStringAsync().Result