替换包装器手册中的模板

Question

我正在尝试为厨师石墨回购写一个包装食谱

在配方carbon.rb中,出现以下行:

template "#{node['graphite']['base_dir']}/conf/storage-schemas.conf" do
  owner node['apache']['user']
  group node['apache']['group']
end

在templates/default/storage-schemas.conf中有一个不受我喜欢的storage-schemas.conf文件.我可以内联编辑文件并实现我想要的,但如果我希望能够在不发生合并冲突的情况下保持我的仓库更新,它似乎不是一个好厨师的做法.所以我想知道我是否可以用包装食谱来解决这个问题.

我的第一个虽然是这样的

include_recipe "graphite"
template "#{node['graphite']['base_dir']}/conf/storage-schemas.conf" do
  owner node['apache']['user']
  group node['apache']['group']
end

我将在基本配方完成后重新运行命令,并将我想要的文件放在wrappercookbook/templates/storage-schemas.conf.erb中.这是一种常见做法吗？它感觉不太干,但我想不出更干净的方式.

Answer 1

你很亲密.假设您的包装器手册中有storage-schemas.conf.erb文件的修改版本,您可以这样做:

include_recipe "graphite"
begin
  r = resources(:template => "#{node['graphite']['base_dir']}/conf/storage-schemas.conf")
  r.cookbook "my-cookbook"
rescue Chef::Exceptions::ResourceNotFound
  Chef::Log.warn "could not find template to override!"
end

您还可以使用以下行:

r.source "graphite-stuff/my-storage-schemas.conf.erb"

如果您想以不同的方式组织包装器菜谱中的文件.

Answer 2

作为Dave答案的替代品,您也可以使用chef-rewind.

https://github.com/bryanwb/chef-rewind

来自github repo的快速使用示例

#file postgresql/recipes/server.rb

template "/var/pgsql/data/postgresql.conf" do
  source  "postgresql.conf.erb"
  owner "postgres"
end

#file my-postgresql/recipes/server.rb

chef_gem "chef-rewind"
require 'chef/rewind'

include_recipe "postgresql::server"
# my-postgresql.conf.erb located inside my-postgresql/templates/default/my-postgresql.conf.erb
rewind :template => "/var/pgsql/data/postgresql.conf" do
  source "my-postgresql.conf.erb"
  cookbook_name "my-postgresql"
end