Sg1*_*456 38 mysql temporary auto-increment
如何使用MySQL在select语句中创建和自动增加临时列?
这是我到目前为止:
SET @cnt = 0;
SELECT
(@cnt =@cnt + 1) AS rowNumber,
rowID
FROM myTable
WHERE CategoryID = 1
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哪个回报:
+++++++++++++++++++++
+ rowNumber | rowID +
+++++++++++++++++++++
+ (NULL) | 1 +
+ (NULL) | 25 +
+ (NULL) | 33 +
+ (NULL) | 150 +
+ (NULL) | 219 +
+++++++++++++++++++++
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但是我需要:
+++++++++++++++++++++
+ rowNumber | rowID +
+++++++++++++++++++++
+ 1 | 1 +
+ 2 | 25 +
+ 3 | 33 +
+ 4 | 150 +
+ ... | ... +
+++++++++++++++++++++
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Ker*_*mit 80
这将为您提供连续的行号3.
SELECT
(@cnt := @cnt + 1) AS rowNumber,
t.rowID
FROM myTable AS t
CROSS JOIN (SELECT @cnt := 0) AS dummy
WHERE t.CategoryID = 1
ORDER BY t.rowID ;
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结果
| ROWNUMBER | ROWID | --------------------- | 1 | 1 | | 2 | 25 | | 3 | 33 | | 4 | 150 |
Nie*_*els 22
试试这个:
SET @rownr=0;
SELECT @rownr:=@rownr+1 AS rowNumber, rowID
FROM myTable
WHERE CategoryID = 1
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在现代版本的MySQL中,您可以使用MySQL窗口:http://www.mysqltutorial.org/mysql-window-functions/mysql-row_number-function/
例:
SELECT ROW_NUMBER() OVER ( ORDER BY productName ) row_num,
productName, msrp
FROM products ORDER BY productName;
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小智 19
但是如果你group by在select语句中有一个怎么办?计算将关闭.
对于这种情况,我找到的唯一解决方案是嵌套选择:
SELECT (@cnt := @cnt + 1) AS rowNumber, t.*
from
(select
t.rowID
FROM myTable
WHERE CategoryID = 1
ORDER BY rowID) t
CROSS JOIN (SELECT @cnt := 0) AS dummy
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