如何在java play框架中获取查询字符串参数？

Question

我是java play框架的新手.我已经设置了所有正常路线,如/ something /:somthingValue和所有其他路线.现在我想创建路由接受查询参数,如

/东西？X = 10&y = 20&Z = 30

在这里,我希望在"？"之后获得所有参数 as key ==> value pair.

Answer 1

您可以将查询参数连接到routes文件中:

http://www.playframework.com/documentation/2.0.4/JavaRouting在"具有默认值的参数"部分

或者你可以在你的行动中要求他们:

public class Application extends Controller {

    public static Result index() {
        final Set<Map.Entry<String,String[]>> entries = request().queryString().entrySet();
        for (Map.Entry<String,String[]> entry : entries) {
            final String key = entry.getKey();
            final String value = Arrays.toString(entry.getValue());
            Logger.debug(key + " " + value);
        }
        Logger.debug(request().getQueryString("a"));
        Logger.debug(request().getQueryString("b"));
        Logger.debug(request().getQueryString("c"));
        return ok(index.render("Your new application is ready."));
    }
}

例如http://localhost:9000/?a=1&b=2&c=3&c=4控制台上的打印件:

[debug] application - a [1]
[debug] application - b [2]
[debug] application - c [3, 4]
[debug] application - 1
[debug] application - 2
[debug] application - 3

请注意,c在网址中是两次.

Answer 2

在Play 2.5.x中,它直接在conf/routes,可以放置默认值:

# Pagination links, like /clients?page=3
GET   /clients              controllers.Clients.list(page: Int ?= 1)

在你的情况下(使用字符串时)

GET   /something            controllers.Somethings.show(x ?= "0", y ?= "0", z ?= "0")

使用强类型时:

GET   /something            controllers.Somethings.show(x: Int ?= 0, y: Int ?= 0, z: Int ?= 0)

请参阅:https://www.playframework.com/documentation/2.5.x/JavaRouting#Parameters-with-default-values以获得更长的解释.

Answer 3

您可以将所有查询字符串参数作为Map获取:

Controller.request().queryString()

此方法返回一个Map<String, String[]>对象.