symfony2 doctrine expr子查询：错误：参数编号无效

Question

尝试按用户获取喜欢的状态。

public function getLikedStatuses(User $user)
{
    $qb = $this->_em->createQueryBuilder();
                $qb
                ->select('s.id')
                ->from('WallBundle:Likes','l')
                ->innerJoin('l.status', 's')
                ->where('l.user = :user')
                ->setParameter('user', $user)
                ->orderBy('s.id','DESC')
            ;

    $qb2=  $this->_em->createQueryBuilder()
        ->select('st')
        ->from('WallBundle:Status','st');

       $qb2 ->andWhere($qb2->expr()->in('st.id',$qb->getDQL()));


    return $qb2->getQuery()->getResult();
}

错误：无效的参数编号：绑定变量的数量与令牌的数量不匹配

顺便说一句：当我转储$ qb-> getDQL（）时：

string 'SELECT s.id FROM TB\WBundle\Entity\Likes l LEFT JOIN l.status s WHERE l.user = :user' (length=87)

BTW2：当我用（12073）（状态ID）替换'$ qb-> getDQL（）'时，它起作用了...

Answer 1

由于原则在使用子查询时不支持限制（请参阅我的评论），一种可能的解决方案是执行两个单独的查询，这并不理想，但可行。

/**
 * @param User $user
 * @param int $limit
 * @param int $offset
 * @return User[]
 */
public function getUserFollowers(User $user, $limit = 20, $offset = 0)
{
    $_followersIds = $this->getEntityManager()
        ->createQueryBuilder()
        ->select('IDENTITY(r.followeduser)')
        ->from($this->getEntityName(), 'r')
        ->where('r.followeeuser = :user')
        ->andWhere('r.followeduser !=:user')
        ->setParameter('user', $user)
        ->orderBy('r.id', 'DESC')
        ->setFirstResult($offset)
        ->setMaxResults($limit)
        ->getQuery()
        ->getResult();

    $_usersQb = $this->getEntityManager()->createQueryBuilder();
    $_usersQb
        ->select('u')
        ->from('UserBundle:User', 'u')
        ->where('u.id IN (:followersIds)')
        ->setParameter('followersIds', array_values($_followersIds));

    return $_usersQb->getQuery()->getResult();
}