如何在angularJS中过滤多个值(OR运算)

Jus*_*cha 132 javascript angularjs angularjs-ng-repeat

我想使用filterin angular并想要过滤多个值,如果它有任何一个值,那么它应该显示.

我有这样的结构:

一个movie具有属性的对象,genres我想过滤ActionComedy.

我知道我可以做filter:({genres: 'Action'} || {genres: 'Comedy'}),但如果我想动态过滤该怎么办.例如filter: variableX

如何设置variableX$scope,当我有我有过滤类型的数组?

我可以把它构造成一个字符串,然后做一个eval()但我不想使用eval()...

Xes*_*ued 87

我只想创建一个自定义过滤器.他们并不那么难.

angular.module('myFilters', []).
  filter('bygenre', function() {
    return function(movies,genres) {
      var out = [];
      // Filter logic here, adding matches to the out var.
      return out;
    }
  });
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模板:

<h1>Movies</h1>

<div ng-init="movies = [
          {title:'Man on the Moon', genre:'action'},
          {title:'Meet the Robinsons', genre:'family'},
          {title:'Sphere', genre:'action'}
       ];" />
<input type="checkbox" ng-model="genrefilters.action" />Action
<br />
<input type="checkbox" ng-model="genrefilters.family" />Family
<br />{{genrefilters.action}}::{{genrefilters.family}}
<ul>
    <li ng-repeat="movie in movies | bygenre:genrefilters">{{movie.title}}: {{movie.genre}}</li>
</ul>
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这里编辑链接:创建角度过滤器

更新:这是一个小提琴,有一个我的建议的精确演示.


jla*_*eau 79

您可以使用控制器功能进行过滤.

function MoviesCtrl($scope) {

    $scope.movies = [{name:'Shrek', genre:'Comedy'},
                     {name:'Die Hard', genre:'Action'},
                     {name:'The Godfather', genre:'Drama'}];

    $scope.selectedGenres = ['Action','Drama'];

    $scope.filterByGenres = function(movie) {
        return ($scope.selectedGenres.indexOf(movie.genre) !== -1);
    };

}
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HTML:

<div ng-controller="MoviesCtrl">
    <ul>
        <li ng-repeat="movie in movies | filter:filterByGenres">
            {{ movie.name }} {{ movie.genre }}
        </li>
    </ul>
</div>
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chr*_*arx 23

在这里创建自定义过滤器可能有点过分,如果您有多个值,则可以传入自定义比较器:

$scope.selectedGenres = "Action, Drama"; 

$scope.containsComparator = function(expected, actual){  
  return actual.indexOf(expected) > -1;
};
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然后在过滤器中:

filter:{name:selectedGenres}:containsComparator
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  • 应该接受答案.谢谢! (2认同)

小智 17

这是自定义过滤器的实现,它将使用值数组过滤数据.它将支持具有数组和单个键值的多个键对象.正如inangularJS API中所提到的,AngularJS过滤器Doc支持多个具有单值的键过滤器,但是下面的自定义过滤器将支持与angularJS相同的功能,并且还支持值数组以及数组和单个键组合的组合.请在下面找到代码片段,

myApp.filter('filterMultiple',['$filter',function ($filter) {
return function (items, keyObj) {
    var filterObj = {
        data:items,
        filteredData:[],
        applyFilter : function(obj,key){
            var fData = [];
            if (this.filteredData.length == 0)
                this.filteredData = this.data;
            if (obj){
                var fObj = {};
                if (!angular.isArray(obj)){
                    fObj[key] = obj;
                    fData = fData.concat($filter('filter')(this.filteredData,fObj));
                } else if (angular.isArray(obj)){
                    if (obj.length > 0){
                        for (var i=0;i<obj.length;i++){
                            if (angular.isDefined(obj[i])){
                                fObj[key] = obj[i];
                                fData = fData.concat($filter('filter')(this.filteredData,fObj));    
                            }
                        }

                    }
                }
                if (fData.length > 0){
                    this.filteredData = fData;
                }
            }
        }
    };
    if (keyObj){
        angular.forEach(keyObj,function(obj,key){
            filterObj.applyFilter(obj,key);
        });
    }
    return filterObj.filteredData;
}
}]);
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用法:

arrayOfObjectswithKeys | filterMultiple:{key1:['value1','value2','value3',...etc],key2:'value4',key3:[value5,value6,...etc]}
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这是一个小提琴示例,实现了上面的"filterMutiple"自定义过滤器. :::小提琴示例:::


小智 13

如果你想过滤对象阵列,你可以给

filter:({genres: 'Action', key :value }.

个别属性将通过为该属性指定的特定过滤器进行过滤.

但是如果您想要通过单个属性过滤并对所有属性进行全局过滤,那么您可以执行类似这样的操作.

<tr ng-repeat="supp in $data | filter : filterObject |  filter : search">
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其中"filterObject"是用于搜索单个属性的对象,"Search"将在全局搜索每个属性.

〜阿图尔


s.a*_*lem 9

我已经花了一些时间在它上面并且感谢@chrismarx,我看到angular的默认filterFilter允许你传递自己的比较器.这是多个值的编辑比较器:

  function hasCustomToString(obj) {
        return angular.isFunction(obj.toString) && obj.toString !== Object.prototype.toString;
  }
  var comparator = function (actual, expected) {
    if (angular.isUndefined(actual)) {
      // No substring matching against `undefined`
      return false;
    }
    if ((actual === null) || (expected === null)) {
      // No substring matching against `null`; only match against `null`
      return actual === expected;
    }
    // I edited this to check if not array
    if ((angular.isObject(expected) && !angular.isArray(expected)) || (angular.isObject(actual) && !hasCustomToString(actual))) {
      // Should not compare primitives against objects, unless they have custom `toString` method
      return false;
    }
    // This is where magic happens
    actual = angular.lowercase('' + actual);
    if (angular.isArray(expected)) {
      var match = false;
      expected.forEach(function (e) {
        e = angular.lowercase('' + e);
        if (actual.indexOf(e) !== -1) {
          match = true;
        }
      });
      return match;
    } else {
      expected = angular.lowercase('' + expected);
      return actual.indexOf(expected) !== -1;
    }
  };
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如果我们想为DRY制作自定义过滤器:

angular.module('myApp')
    .filter('filterWithOr', function ($filter) {
      var comparator = function (actual, expected) {
        if (angular.isUndefined(actual)) {
          // No substring matching against `undefined`
          return false;
        }
        if ((actual === null) || (expected === null)) {
          // No substring matching against `null`; only match against `null`
          return actual === expected;
        }
        if ((angular.isObject(expected) && !angular.isArray(expected)) || (angular.isObject(actual) && !hasCustomToString(actual))) {
          // Should not compare primitives against objects, unless they have custom `toString` method
          return false;
        }
        console.log('ACTUAL EXPECTED')
        console.log(actual)
        console.log(expected)

        actual = angular.lowercase('' + actual);
        if (angular.isArray(expected)) {
          var match = false;
          expected.forEach(function (e) {
            console.log('forEach')
            console.log(e)
            e = angular.lowercase('' + e);
            if (actual.indexOf(e) !== -1) {
              match = true;
            }
          });
          return match;
        } else {
          expected = angular.lowercase('' + expected);
          return actual.indexOf(expected) !== -1;
        }
      };
      return function (array, expression) {
        return $filter('filter')(array, expression, comparator);
      };
    });
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然后我们可以在任何我们想要的地方使用它:

$scope.list=[
  {name:'Jack Bauer'},
  {name:'Chuck Norris'},
  {name:'Superman'},
  {name:'Batman'},
  {name:'Spiderman'},
  {name:'Hulk'}
];


<ul>
  <li ng-repeat="item in list | filterWithOr:{name:['Jack','Chuck']}">
    {{item.name}}
  </li>
</ul>
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最后,这是一个傻瓜.

注意:预期数组应该只包含String,Number等简单对象.


a8m*_*a8m 7

您可以使用searchField过滤angular.filter

JS:

$scope.users = [
 { first_name: 'Sharon', last_name: 'Melendez' },
 { first_name: 'Edmundo', last_name: 'Hepler' },
 { first_name: 'Marsha', last_name: 'Letourneau' }
];
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HTML:

<input ng-model="search" placeholder="search by full name"/> 
<th ng-repeat="user in users | searchField: 'first_name': 'last_name' | filter: search">
  {{ user.first_name }} {{ user.last_name }}
</th>
<!-- so now you can search by full name -->
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  • 您还可以使用angular.filter中的"where"<tr ng-repeat ="obj in collection | where:{id:1}"> {{obj.name}} </ tr> (3认同)

cyb*_*bat 7

ngIf如果情况允许,您也可以使用:

<div ng-repeat="p in [
 { name: 'Justin' }, 
 { name: 'Jimi' }, 
 { name: 'Bob' }
 ]" ng-if="['Jimi', 'Bob'].indexOf(e.name) > -1">
 {{ p.name }} is cool
</div>
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Pri*_*mre 7

我发现最快的解决办法是使用filterBy过滤器从角滤波器,例如:

<input type="text" placeholder="Search by name or genre" ng-model="ctrl.search"/>   
<ul>
  <li ng-repeat="movie in ctrl.movies | filterBy: ['name', 'genre']: ctrl.search">
    {{movie.name}} ({{movie.genre}}) - {{movie.rating}}
  </li>
</ul>
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好处是角度过滤器是一个相当受欢迎的库(GitHub上约2.6k星),它仍然在积极开发和维护,所以将它作为依赖项添加到项目中应该没问题.