Pav*_*sov 16
您可以通过两个查询和一些逻辑来获取它:
我们的想法是在目标日期时间之后立即找到一个对象,然后返回其中一个:
# this method is on the model's manager
def get_closest_to(self, target)
closest_greater_qs = self.filter(dt__gt=target).order_by('dt')
closest_less_qs = self.filter(dt__lt=target).order_by('-dt')
try:
try:
closest_greater = closest_greater_qs[0]
except IndexError:
return closest_less_qs[0]
try:
closest_less = closest_less_qs[0]
except IndexError:
return closest_greater_qs[0]
except IndexError:
raise self.model.DoesNotExist("There is no closest object"
" because there are no objects.")
if closest_greater.dt - target > target - closest_less.dt:
return closest_less
else:
return closest_greater
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要使用一个查询来获取它,您必须将ORM退出到原始SQL.
只需将帕夫勒的答案更改为:
def get_closest_to_dt(qs, dt):
greater = qs.filter(dt__gte=dt).order_by("dt").first()
less = qs.filter(dt__lte=dt).order_by("-dt").first()
if greater and less:
return greater if abs(greater.dt - dt) < abs(less.dt - dt) else less
else:
return greater or less
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