结构矢量:添加元素C++

Question

我正在从文件中读取我的结构,我想将它们添加到结构的向量中.以下是它的外观和工作原理:

    typedef struct
{
    int ID;
    string name;
    string surname;
    int points;
}
Student;

int main()
{
    ifstream theFile("test.txt");
    std::vector<Student*> students;

    Student* s = new Student();

    while(theFile >> s->ID >> s->name >> s->surname >> s->points)
    {
        studenti.push_back(s); // here I would like to add this struct s from a file
    }

// here I want to print each struct's values on the screen, but the output is always ONLY last struct N times, and not all of them, each only once


    std::vector<Student*>::const_iterator it;
    for(it = students.begin(); it != students.end(); it+=1)
    {
        std::cout << (*it)->ID <<" " << (*it)->name << " " << (*it)->surname <<" " << (*it)->points <<endl;
    }

我应该怎么做才能将我的结构添加到矢量中,并将它们正常打印出来(如果结构正确加载到矢量中,这个打印真的只是一个检查)？

Answer 1

你的错误是使用指针

std::vector<Student> students;

Student s;
while(theFile >> s.ID >> s.name >> s.surname >> s.points)
{
    students.push_back(s);
}

现在它会起作用.

问题是你一遍又一遍地重复使用相同的指针.所以你最终会得到一个指向同一个对象的指针向量.哪个将有最后一个学生读入的值.

当更简单的一个是正确的时候,选择复杂的替代方案似乎是一个相当普遍的初学者特征,所以我很想知道为什么你选择使用指针.

Answer 2

以下是现代C++中代码的外观:

#include <string>
#include <istream>
#include <vector>

struct Student
{
    int ID;
    std::string name;
    std::string surname;
    int points;

    Student(int i, std::string n, std::string s, int p)
    : ID(i), name(std::move(n)), surname(std::move(s)), points(p) {}
};

std::vector<Student> read_students(std::istream & is)
{
    std::vector<Student> result;

    std::string name, surname;
    int id, points;

    while (is >> id >> name >> surname >> points)
    {
        result.emplace_back(id, name, surname, points);
    }

    return result;
}

用法:

#include <fstream>
#include <iostream>

int main()
{
    std::ifstream infile("test.txt");
    auto students = read_students(infile);

    // ...
}