创建简单的手势,从左到右,从右到左滑动

Question

我想在两个活动之间创建简单的滑动手势,我已经搜索了很多类似下面的内容.但我怀疑的是我如何使用滑动手势滑动活动或视图!

class MyGestureDetector extends SimpleOnGestureListener {
        @Override
        public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY) {
            try {
                if (Math.abs(e1.getY() - e2.getY()) > SWIPE_MAX_OFF_PATH)
                    return false;
                // right to left swipe
                if(e1.getX() - e2.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY) {
                    Toast.makeText(SelectFilterActivity.this, "Left Swipe", Toast.LENGTH_SHORT).show();
                }  else if (e2.getX() - e1.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY) {
                    Toast.makeText(SelectFilterActivity.this, "Right Swipe", Toast.LENGTH_SHORT).show();
                }
            } catch (Exception e) {
                // nothing
            }
            return false;
        }

希望有人能帮助我@Thanks!

Answer 1

立即试用此代码..

page = (LinearLayout) findViewById(R.id.flipper);

@Override
public boolean dispatchTouchEvent(MotionEvent event) {
    super.dispatchTouchEvent(event);
    return gestureDetector.onTouchEvent(event);
}

SimpleOnGestureListener simpleOnGestureListener = new SimpleOnGestureListener() {

    @Override
    public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX,
            float velocityY) {

        float sensitvity = 50;
        if ((e1.getX() - e2.getX()) > sensitvity) {
            SwipeLeft();
        } else if ((e2.getX() - e1.getX()) > sensitvity) {
            SwipeRight();
        }

        return true;
    }

};

 GestureDetector gestureDetector = new GestureDetector(
        simpleOnGestureListener);



private void SwipeLeft() {

     page.setInAnimation(animFlipInForeward);
      page.setOutAnimation(animFlipOutForeward);
      page.showNext();

}


 private void SwipeRight() { 

     page.setInAnimation(animFlipInBackward);
     page.setOutAnimation(animFlipOutBackward);
     page.showPrevious();

}