列出文件并使用bash在菜单中显示它们

Question

我试图将目录中的文件用作bash脚本中的选项.用户应该能够选择一个,然后将所选文件的名称传递给变量.到目前为止,我可以获取文件列表,但经过几个小时的尝试后,我无法弄清楚如何将它们显示为选项.

#!/bin/bash
prompt="Please select a file:"
options=( $(find -maxdepth 1 -print0 | xargs -0) )

PS3="$prompt "
select opt in "${options[@]}" "Quit"; do 

    case "$REPLY" in
    for i in "${options[@]}"
    do
    $i' ) echo "You picked $opt which is file $REPLY";;'
    done    
    $(( ${#options[@]}+1 )) ) echo "Goodbye!"; break;;
    *) echo "Invalid option. Try another one.";continue;;

    esac

done

任何帮助深表感谢.谢谢!

Answer 1

我不认为case这里适合:

#!/bin/bash
prompt="Please select a file:"
options=( $(find -maxdepth 1 -print0 | xargs -0) )

PS3="$prompt "
select opt in "${options[@]}" "Quit" ; do 
    if (( REPLY == 1 + ${#options[@]} )) ; then
        exit

    elif (( REPLY > 0 && REPLY <= ${#options[@]} )) ; then
        echo  "You picked $opt which is file $REPLY"
        break

    else
        echo "Invalid option. Try another one."
    fi
done    

ls -ld $opt