用Python构建URL的库

Question

我需要找到一个库来构建python中的URL,如:

http://subdomain.domain.com?arg1=someargument&arg2=someotherargument

您会建议使用哪个库？为什么？这种图书馆有"最佳"选择吗？

Answer 1

我会选择Python urllib,它是一个内置库.

# Python 2:
import urllib

# Python 3:
# import urllib.parse

getVars = {'var1': 'some_data', 'var2': 1337}
url = 'http://domain.com/somepage/?'

# Python 2:
print(url + urllib.urlencode(getVars))

# Python 3:
# print(url + urllib.parse.urlencode(getVars))

输出:

http://domain.com/somepage/?var2=1337&var1=some_data

Answer 2

urlparse在python标准库中,所有关于构建有效的URL.查看urlparse的文档

Answer 3

以下是urlparse用于生成URL 的示例.这样可以方便地添加URL的路径,而无需担心检查斜杠.

import urllib
import urlparse

def build_url(baseurl, path, args_dict):
    # Returns a list in the structure of urlparse.ParseResult
    url_parts = list(urlparse.urlparse(baseurl))
    url_parts[2] = path
    url_parts[4] = urllib.urlencode(args_dict)
    return urlparse.urlunparse(url_parts)

args = {'arg1': 'value1', 'arg2': 'value2'}
# works with double slash scenario
url1 = build_url('http://www.example.com/', '/somepage/index.html', args)
print(url1)

>>> http://www.example.com/somepage/index.html?arg1=value1&arg2=value2

# works without slash
url2 = build_url('http://www.example.com', 'somepage/index.html', args)
print(url2)

>>> http://www.example.com/somepage/index.html?arg1=value1&arg2=value2

Answer 4

import requests
payload = {'key1':'value1', 'key2':'value2'}
response =  requests.get('http://fireoff/getdata', params=payload)
print response.url

打印： http：// fireoff / getdata？key1 = value1＆key2 = value2

Answer 5

import urllib

def make_url(base_url , *res, **params):
    url = base_url
    for r in res:
        url = '{}/{}'.format(url, r)
    if params:
        url = '{}?{}'.format(url, urllib.urlencode(params))
    return url

>>>print make_url('http://example.com', 'user', 'ivan', aloholic='true', age=18)

http://example.com/user/ivan?age=18&aloholic=true