San*_*ite -3 iphone xcode json objective-c ios
我想解析一个普通的JSON数组,如:
{
"ns": [
[
"1364987475027",
"Alert1",
"001"
],
[
"1364987475042",
"Alert2",
"001"
],
[
"1364987475058",
"Alert4",
"001"
]
]
}
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将数组放入简单的字符串数组中.我发现很多帖子都带有JSON字典数组.但在这种情况下,JSON没有值的键.请帮助.
Bha*_*vin 16
答案: NSJSONSerialization.
NSJSONSerializationclass可用于将JSON转换为Foundation对象,将Foundation对象转换为JSON.在你的情况,你应该使用-JSONObjectWithData:options:error:的NSJSONSerialization类从给定的JSON数据检索Foundation对象.
示例代码:
NSError *error;
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error];
NSArray *fetchedArr = [json objectForKey:@"ns"];
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