我希望能够在使用Roslyn解析C#源代码时阅读XML文档注释.
/// <summary>
/// Documentation...
/// </summary>
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我尝试在ParseOptions中设置ParseDocumentationComments,但它似乎没有效果?
var parseOptions = ParseOptions.Default.WithParseDocumentationComments(true);
SyntaxTree unit = SyntaxTree.ParseFile(file, parseOptions);
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Kev*_*lch 29
你需要:
LeadingTrivia
包含XML doc注释的语法Compilation
,找到Symbol
具有XML doc注释并使用该GetDocumentationComment()
方法的方法.一个完整的例子:
using Roslyn.Compilers.CSharp;
using System;
using System.Linq;
class Program
{
static void Main(string[] args)
{
var tree = SyntaxTree.ParseText(@"
/// <summary>This is an xml doc comment</summary>
class C
{
}");
var classNode = (ClassDeclarationSyntax)tree.GetRoot().Members.First();
var trivia = classNode.GetLeadingTrivia().Single(t => t.Kind == SyntaxKind.DocumentationCommentTrivia);
var xml = trivia.GetStructure();
Console.WriteLine(xml);
var compilation = Compilation.Create("test", syntaxTrees: new[] { tree });
var classSymbol = compilation.GlobalNamespace.GetTypeMembers("C").Single();
var docComment = classSymbol.GetDocumentationComment();
Console.WriteLine(docComment.SummaryTextOpt);
}
}
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只是为了更新Kevin Pilch上面的回答:
通过nuget添加Microsoft.CodeAnalysis.CSharp
代码如下:
using System;
using System.Linq;
using Microsoft.CodeAnalysis.CSharp;
using Microsoft.CodeAnalysis.CSharp.Syntax;
class Program
{
static void Main(string[] args)
{
var tree = CSharpSyntaxTree.ParseText(@"
/// <summary> This is an xml doc comment </summary>
class C
{
}");
var root = (CompilationUnitSyntax) tree.GetRoot();
var classNode = (ClassDeclarationSyntax) (root.Members.First());
var trivias = classNode.GetLeadingTrivia();
var xmlCommentTrivia = trivias.FirstOrDefault(t => t.Kind() == SyntaxKind.SingleLineDocumentationCommentTrivia);
var xml = xmlCommentTrivia.GetStructure();
Console.WriteLine(xml);
var compilation = CSharpCompilation.Create("test", syntaxTrees: new[] {tree});
var classSymbol = compilation.GlobalNamespace.GetTypeMembers("C").Single();
var docComment = classSymbol.GetDocumentationCommentXml();
Console.WriteLine(docComment);
}
}
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