在SQL Server 2005中将列显示为行

use*_*794 6 sql t-sql pivot sql-server-2005

我已经阅读了几十个解决类似换位问题的解决方案,就像我即将提出的问题一样,但奇怪的是没有一个能够完全反映我的问题.我只是想在一个简单的仪表板类型数据集中将我的行翻转到列.

从各种事务表中提取的数据如下所示:

DatePeriod  PeriodNumberOverall   Transactions   Customers   Visits

'Jan 2012'   1                    100            50          150
'Feb 2012'   2                    200            100         300
'Mar 2012'   3                    300            200         600
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我希望能够生成以下内容:

                      Jan 2012   Feb 2012   Mar 2012

Transactions          100        200        300
Customers             50         100        200
Visits                150        300        600
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指标将是静态的(交易,客户和访问),但日期周期将是动态的(IE - 随着月份的增加而增加).

再一次,我已经准备好了许多利用pivot,unpivot,存储过程,UNION ALLs等的例子,但没有任何我没有做任何聚合的事情,只是字面上转换整个输出.我还在Visual Studio 2005中使用带有嵌入列表的矩阵找到了一种简单的方法,但我无法将最终输出导出到excel,这是一项要求.任何帮助将不胜感激.

Tar*_*ryn 2

为了获得您想要的结果,您需要首先获取UNPIVOT数据,然后获取PIVOT theDatePeriod` 值。

UNPIVOT 会将Transactions,Customers和的多列转换Visits为多行。其他答案是使用 a来取消透视,但 SQL Server 2005 是支持UNION ALL该功能的第一年。UNPIVOT

取消透视数据的查询是:

select dateperiod,
  col, value
from transactions
unpivot
(
  value for col in (Transactions, Customers, Visits)
) u
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请参阅演示。这会将当前列转换为多行,因此数据如下所示:

| DATEPERIOD |          COL | VALUE |
-------------------------------------
|   Jan 2012 | Transactions |   100 |
|   Jan 2012 |    Customers |    50 |
|   Jan 2012 |       Visits |   150 |
|   Feb 2012 | Transactions |   200 |
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现在,由于数据位于行中,因此您可以将该PIVOT函数应用于DatePeriod列:

select col, [Jan 2012], [Feb 2012], [Mar 2012]
from
(
  select dateperiod,
    t.col, value, c.SortOrder
  from
  (
    select dateperiod,
      col, value
    from transactions
    unpivot
    (
      value for col in (Transactions, Customers, Visits)
    ) u
  ) t
  inner join
  (
    select 'Transactions' col, 1 SortOrder
    union all
    select 'Customers' col, 2 SortOrder
    union all
    select 'Visits' col, 3 SortOrder
   ) c
    on t.col = c.col
) d
pivot
(
  sum(value)
  for dateperiod in ([Jan 2012], [Feb 2012], [Mar 2012])
) piv
order by SortOrder;
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请参阅SQL Fiddle 演示

如果您的日期周期数量未知,那么您将使用动态 SQL:

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT ',' + QUOTENAME(dateperiod) 
                    from transactions
                    group by dateperiod, PeriodNumberOverall
                    order by PeriodNumberOverall
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT col, ' + @cols + ' 
             from 
             (
                select dateperiod,
                  t.col, value, c.SortOrder
                from
                (
                  select dateperiod,
                    col, value
                  from transactions
                  unpivot
                  (
                    value for col in (Transactions, Customers, Visits)
                  ) u
                ) t
                inner join
                (
                  select ''Transactions'' col, 1 SortOrder
                  union all
                  select ''Customers'' col, 2 SortOrder
                  union all
                  select ''Visits'' col, 3 SortOrder
                 ) c
                  on t.col = c.col
            ) x
            pivot 
            (
                sum(value)
                for dateperiod in (' + @cols + ')
            ) p 
            order by SortOrder'

execute(@query)
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请参阅SQL Fiddle 演示。两者都会给出结果:

|          COL | JAN 2012 | FEB 2012 | MAR 2012 |
-------------------------------------------------
| Transactions |      100 |      200 |      300 |
|    Customers |       50 |      100 |      200 |
|       Visits |      150 |      300 |      600 |
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