CakePHP 2.3 - 单元测试用户登录

Question

我想我必须在这里问一些帮助我的问题.我整个晚上都在这.我有这样的登录方法UsersController:

public function login() {

        if ( $this->request->is( 'post' ) ) {
            if ( $this->Auth->login() ) {
                $this->redirect( array( 'controller' => 'reservations', 'action' => 'index' ) );
            } else {
                $this->Session->setFlash( __( 'Login error.' ), 'flashError' );
            }
        }
    }

我试图用PHPUnit测试这个,所以我可以确定只有有效的用户可以登录→成功登录后,他们将被重定向到特定的页面.这是我testLogin在UsersControllerTest课堂上的方法:

function testLogin() {

        $UsersController = $this->generate( 'Users', array(
                'components' => array(
                    'Auth' => array( 'user' )
                ),
            )
        );

        $UsersController->Auth->expects( $this->any() )
        ->method( 'user' )
        ->with( 'id' )
        ->will( $this->returnValue( 2 ) );

        $data = array( 'User' => array(
                'student_number' => 1111111,
                'password' => 'qwerty'
            ) );

        //$UsersController->Auth->login( $data['User'] );

        $this->testAction( '/users/login', array( 'data' => $data, 'method' => 'get' ) );
        $url = parse_url( $this->headers['Location'] );
        $this->assertEquals( $url['path'], '/reservations' );
    }

我还在学习使用CakePHP进行单元测试的基础知识.我收到此错误:

PHPUNIT_FRAMEWORK_ERROR_NOTICE
Undefined index: Location
Test case: UsersControllerTest(testLogin)

我不知道是什么导致这个...我的测试方法有什么问题以及它应该如何编写？

谢谢!

Answer 1

我使用以下代码得到了这个工作：

function testLogin() {

        //mock user
        $this->Users = $this->generate( 'Users', array(
                'components' => array(
                    'Security' => array( '_validatePost' ),
                )
            ) );

        //create user data array with valid info
        $data = array();
        $data['User']['student_number'] = 1234567;
        $data['User']['password'] = '[valid password here]';

        //test login action
        $result = $this->testAction( "/users/login", array(
                "method" => "post",
                "return" => "contents",
                "data" => $data
            )
        );

        $foo[] = $this->view;
        //debug($foo);

        //test successful login
        $this->assertNotNull( $this->headers['Location'] );
        $this->assertContains( 'reservations', $this->headers['Location'] );
        $this->assertNotContains( '"/users/login" id="UserLoginForm"', $foo );

        //logout mocked user
        $this->Users->Auth->logout();
    }