如何在PHP中运行bind_param()语句？

Question

我正在尝试使以下代码工作,但我无法达到这execute()条线.

$mysqli = $this->ConnectLowPrivileges();
echo 'Connected<br>';
$stmt = $mysqli->prepare("SELECT `name`, `lastname` FROM `tblStudents` WHERE `idStudent`=?");
echo 'Prepared and binding parameters<br>';
$stmt->bind_param('i', 2 );
echo 'Ready to execute<br>'
if ($stmt->execute()){
    echo 'Executing..';
    }
} else {
    echo 'Error executing!';
}
mysqli_close($mysqli);

我得到的输出是:

Connected
Prepared and binding parameters

所以问题应该在第5行,但检查我的手册在bind_param()那里找不到任何语法错误.

Answer 1

绑定参数时,需要传递一个用作引用的变量:

$var = 1;

$stmt->bind_param('i', $var);

请参阅手册:http://php.net/manual/en/mysqli-stmt.bind-param.php

请注意,$var实际上不必定义绑定它.以下内容完全有效:

$stmt->bind_param('i', $var);

foreach ($array as $element)
{

    $var = $element['foo'];

    $stmt->execute();

}