Hun*_*hao 2 mysql sql select min
我有一个数据集:
+----+---------------+-------+-------------+---------------------+
| id | ip | port | point_count | create_time |
+----+---------------+-------+-------------+---------------------+
| 1 | 192.168.20.28 | 10000 | 0 | 2013-03-29 14:29:14 |
| 2 | 0.0.0.0 | 10000 | 0 | 2013-03-29 14:29:32 |
| 3 | 0.0.0.1 | 11111 | 2 | 2013-03-29 14:29:38 |
| 4 | 0.0.0.5 | 11112 | 3 | 2013-03-29 14:29:44 |
+----+---------------+-------+-------------+---------------------+
4 rows in set (0.00 sec)
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现在,我使用mysql的MIN()函数来获取记录:
mysql> SELECT s.id, s.ip, s.port, MIN(s.point_count) FROM origin_server s;
+----+---------------+-------+--------------------+
| id | ip | port | MIN(s.point_count) |
+----+---------------+-------+--------------------+
| 1 | 192.168.20.28 | 10000 | 0 |
+----+---------------+-------+--------------------+
1 row in set (0.00 sec)
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显然,有两行具有相同的列point_count值,但它只返回一条记录.我只是想确认这种情况是否正确.提前致谢 :)
您只获得一条记录的原因MIN()是因为是一个聚合函数,它为每个组返回一条记录.由于您尚未指定GROUP BY子句,因此结果是正常的,只给出一条记录.
您可以使用子查询来获取最小值,point_count并将其等同于外部查询 point_count.
SELECT *
FROM origin_server
WHERE point_count = (SELECT MIN(point_count) FROM origin_server)
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OUTPUT
??????????????????????????????????????????????????????????????????
? ID ? IP ? PORT ? POINT_COUNT ? CREATE_TIME ?
??????????????????????????????????????????????????????????????????
? 1 ? 192.168.20.28 ? 10000 ? 0 ? 2013-03-29 14:29:14 ?
? 2 ? 0.0.0.0 ? 10000 ? 0 ? 2013-03-29 14:29:32 ?
??????????????????????????????????????????????????????????????????
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